Angie, Bev, Ceci, and Dina are dividing among themselves a set of common assets equally owned by the four of them. The assets are divided into four shares ( s 1 , s 2 , s 3 and s 4 ) . Table 3-14 shows the values of the shares to each player expressed as a percent of the total value of the assets. Table 3-13 s 1 s 2 s 3 s 4 Angie 22% 26% 28% 24% Bev 25% 26% 22% 27% Ceci 20% 30% 27% 23% Dina 25% 25% 25% 25% a. Which of the shares are fair shares to Angie? b. Which of the shares are fair shares to Bev? c. Which of the shares are fair shares to Ceci? d. Which of the shares are fair shares to Dina? e. Find all possible fair divisions of the assets using s 1 , s 2 , s 3 and s 4 as shares.
Angie, Bev, Ceci, and Dina are dividing among themselves a set of common assets equally owned by the four of them. The assets are divided into four shares ( s 1 , s 2 , s 3 and s 4 ) . Table 3-14 shows the values of the shares to each player expressed as a percent of the total value of the assets. Table 3-13 s 1 s 2 s 3 s 4 Angie 22% 26% 28% 24% Bev 25% 26% 22% 27% Ceci 20% 30% 27% 23% Dina 25% 25% 25% 25% a. Which of the shares are fair shares to Angie? b. Which of the shares are fair shares to Bev? c. Which of the shares are fair shares to Ceci? d. Which of the shares are fair shares to Dina? e. Find all possible fair divisions of the assets using s 1 , s 2 , s 3 and s 4 as shares.
Angie, Bev, Ceci, and Dina are dividing among themselves a set of common assets equally owned by the four of them. The assets are divided into four shares
(
s
1
,
s
2
,
s
3
and
s
4
)
. Table 3-14 shows the values of the shares to each player expressed as a percent of the total value of the assets.
Table 3-13
s
1
s
2
s
3
s
4
Angie
22%
26%
28%
24%
Bev
25%
26%
22%
27%
Ceci
20%
30%
27%
23%
Dina
25%
25%
25%
25%
a. Which of the shares are fair shares to Angie?
b. Which of the shares are fair shares to Bev?
c. Which of the shares are fair shares to Ceci?
d. Which of the shares are fair shares to Dina?
e. Find all possible fair divisions of the assets using
s
1
,
s
2
,
s
3
and
s
4
as shares.
موضوع الدرس
Prove that
Determine the following groups
Homz(QZ) Hom = (Q13,Z)
Homz(Q), Hom/z/nZ, Qt
for neN-
(2) Every factor group of
adivisible group is divisble.
• If R is a Skew ficald (aring with
identity and each non Zero element is
invertible then every R-module is free.
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
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