Consider Example 2a, but now suppose that when the key is in a certain pocket, there is a 10 percent chance that a search of that pocket will not find the key. Let R and L be, respectively, the events that the key is in the right-hand pocket of the jacket and that it is in the left-hand pocket. Also, let S R be the event that a search of the right-hand jacket pocket will be successful in finding the key, and let U L be the event that a search of the left-hand jacket pocket will be unsuccessful and, thus, not find the key. Find P(SRIUL), the conditional probability that a search of the right-hand pocket will find the key given that a search of the left-hand pocket did not, by (a) using the identity P ( S R | U L ) = P ( S R U L ) P ( U L ) determining (SRUL) by conditioning on whether or not the key is in the right-hand pocket, and determining P(UL) by conditioning on whether or not the key is in the left- hand pocket; (b) using the identity P ( S R | U L ) = P ( S R | R U L ) P ( R | U L ) + P ( S R | R C U L ) P ( R C | U L )
Consider Example 2a, but now suppose that when the key is in a certain pocket, there is a 10 percent chance that a search of that pocket will not find the key. Let R and L be, respectively, the events that the key is in the right-hand pocket of the jacket and that it is in the left-hand pocket. Also, let S R be the event that a search of the right-hand jacket pocket will be successful in finding the key, and let U L be the event that a search of the left-hand jacket pocket will be unsuccessful and, thus, not find the key. Find P(SRIUL), the conditional probability that a search of the right-hand pocket will find the key given that a search of the left-hand pocket did not, by (a) using the identity P ( S R | U L ) = P ( S R U L ) P ( U L ) determining (SRUL) by conditioning on whether or not the key is in the right-hand pocket, and determining P(UL) by conditioning on whether or not the key is in the left- hand pocket; (b) using the identity P ( S R | U L ) = P ( S R | R U L ) P ( R | U L ) + P ( S R | R C U L ) P ( R C | U L )
Solution Summary: The author calculates the conditional probability of finding a key in the right-hand pocket of the jacket and not the left-handed pocket.
Consider Example 2a, but now suppose that when the key is in a certain pocket, there is a 10 percent chance that a search of that pocket will not find the key. Let R and L be, respectively, the events that the key is in the right-hand pocket of the jacket and that it is in the left-hand pocket. Also, let
S
R
be the event that a search of the right-hand jacket pocket will be successful in finding the key, and let
U
L
be the event that a search of the left-hand jacket pocket will be unsuccessful and, thus, not find the key. Find P(SRIUL), the conditional probability that a search of the right-hand pocket will find the key given that a search of the left-hand pocket did not, by (a) using the identity
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|
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=
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determining (SRUL) by conditioning on whether or not the key is in the right-hand pocket, and determining P(UL) by conditioning on whether or not the key is in the left- hand pocket; (b) using the identity
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R
|
U
L
)
=
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|
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)
P
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+
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P
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3. A different 7-Eleven has a bank of slurpee fountain heads. Their available flavors are as follows: Mountain
Dew, Mountain Dew Code Red, Grape, Pepsi and Mountain Dew Livewire. You fill five different cups full
with each type of flavor. How many different ways can you arrange the cups in a line if exactly two Mountain
Dew flavors are next to each other?
3.2.1
Answer questions 8.3.3 and 8.3.4 respectively
8.3.4 .WP An article in Medicine and Science in Sports and
Exercise [“Electrostimulation Training Effects on the Physical Performance of Ice Hockey Players” (2005, Vol. 37, pp.
455–460)] considered the use of electromyostimulation (EMS) as
a method to train healthy skeletal muscle. EMS sessions consisted of 30 contractions (4-second duration, 85 Hz) and were carried
out three times per week for 3 weeks on 17 ice hockey players.
The 10-meter skating performance test showed a standard deviation of 0.09 seconds. Construct a 95% confidence interval of the
standard deviation of the skating performance test.
8.6.7 Consider the tire-testing data in Exercise 8.2.3. Compute a 95% tolerance interval on the life of the tires that has confidence level 95%. Compare the length of the tolerance interval with the length of the 95% CI on the population mean. Which interval is shorter? Discuss the difference in interpretation of these two intervals.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, probability and related others by exploring similar questions and additional content below.
Discrete Distributions: Binomial, Poisson and Hypergeometric | Statistics for Data Science; Author: Dr. Bharatendra Rai;https://www.youtube.com/watch?v=lHhyy4JMigg;License: Standard Youtube License