
(a)
Interpretation:
The name of the ionic compound KF needs to be determined.
Concept introduction:
In an ionic compound, a cation is named first, while an anion is named later. As the question contains monoatomic ions, the rules related to the nomenclature of monoatomic ions should be followed.

Answer to Problem 3.74P
Potassium fluoride.
Explanation of Solution
An ionic compound is a combination of a cation (positively charged ion) & an anion (negatively charged ion). This combination results in a charge neutralized stable chemical species.
There is a specific pattern to name an ionic compound. Usually, in a formula of an ionic compound, a cation is presented in the right side, while an anion is in the left side.
Naming of cations
- The naming of the cation is very simple. It is just the writing of the name of the metal element.
- Sometimes there are some metals that form different cations. In that case after the cation name, the charge should be indicated in roman numbers, with in the brackets.
Naming of anions
- To determine the name of the monoatomic anion (anion which has only one type of atom) following rules should be followed. When naming an anion the ending name of the elemental anion should be removed to replace it by "ide". This question contains ionic compounds with monoatomic anions.
These rules will be cleared when using them practically to write the ionic names.
Consider KF. The cation is K+. The only cation related to K is K+. Therefore, 2nd rule of cations is not applied.
KF − Potassium + Fluor(ine)
Within the brackets, it contains the ending of the anion. That part should be removed to replace by "ide".
Potassium + Fluor(ide)
Potassium fluoride.
(b)
Interpretation:
The name of the ionic compound ZnCl2 needs to be determined.
Concept introduction:
In an ionic compound cation is named first, while an anion is named later. As the question contains monoatomic ions, the rules related to the nomenclature of monoatomic ions should be followed.

Answer to Problem 3.74P
Zinc(II) Chloride.
Explanation of Solution
An ionic compound is a combination of a cation (positively charged ion) & an anion (negatively charged ion). This combination results in a charge neutralized stable chemical species.
There is a specific pattern to name an ionic compound. Usually, in a formula of an ionic compound, a cation is presented in the right side, while an anion is in the left side.
Using the described rules, the name of the ionic compound can be derived as follows.
Consider ZnCl2,the cation is Zn2+. So, II should be mentioned within brackets.
ZnCl2 − Zinc(II) + Chlor(ine)
Within the brackets, it contains the ending of the anion. That part should be removed to replace by "ide".
Zinc(II) + Chlor(ide)
Zinc(II) Chloride
(c)
Interpretation:
The name of the ionic compound Cu2Sneeds to be determined.
Concept introduction:
In an ionic compound cation is named first, while an anion is named later. As the question contains monoatomic ions, the rules related to the nomenclature of monoatomic ions should be followed.

Answer to Problem 3.74P
Copper(I) Sulfide.
Explanation of Solution
An ionic compound is a combination of a cation (positively charged ion) & an anion (negatively charged ion). This combination results in a charge neutralized stable chemical species.
There is a specific pattern to name an ionic compound. Usually, in a formula of an ionic compound, a cation is presented in the right side, while an anion is in the left side.
Using the described rules, the name of the ionic compound can be derived as follows.
Consider Cu2S. The cation is Cu+ (Cuprous). Cu has two cations as Cu+ (Cuprous) & Cu2+ (Cupric). So the second rule for cations applies here. So, I should be mentioned within brackets.
Cu2S − Copper(I) + Sulf(ur)
Within the brackets, it contains the ending of the anion. That part should be removed to replace by "ide".
Copper(I) + Sulf(ide)
Copper(I) Sulfide
Copper(I) Sulfide is the name of Cu2S, according to the IUPAC (International Union of Pure and Applied Chemistry) rules of ionic compound nomenclature. Generally, Cu2S also be known as Cuprous Sulfide as Cu+ ion is known as Cuprous ion.
(d)
Interpretation:
The name of the ionic compound SnO needs to be determined.
Concept introduction:
In an ionic compound cation is named first, while an anion is named later. As the question contains monoatomic ions, the rules related to the nomenclature of monoatomic ions should be followed.

Answer to Problem 3.74P
Tin(II) Oxide
Explanation of Solution
An ionic compound is a combination of a cation (positively charged ion) & an anion (negatively charged ion). This combination results in a charge neutralized stable chemical species.
There is a specific pattern to name an ionic compound. Usually, in a formula of an ionic compound, a cation is presented in the right side, while an anion is in the left side.
Using the described rules, the name of the ionic compound can be derived as follows.
Consider SnO, the cation is Sn2+ (Stannous). Sn has two cations as Sn2+ (Stannous) & Sn4+ (Stannic). So the second rule for cations applies here. So II should be mentioned within brackets. The common name for the metal is Tin.
SnO − Tin(II) + Ox(ygen)
Within the brackets, it contains the ending of the anion. That part should be removed to replace by "ide".
Tin(II) + Ox(ide)
Tin(II) Oxide
Tin(II) Oxide is the name of SnO, according to the IUPAC (International Union of Pure and Applied Chemistry) rules of ionic compound nomenclature. Generally, SnO also can be known as Stannous Oxide as Sn2+ ion is known as Stannous ion.
(e)
Interpretation:
The name of the ionic compound AuBr3 needs to be determined.
Concept introduction:
In an ionic compound cation is named first, while an anion is named later. As the question contains monoatomic ions, the rules related to the nomenclature of monoatomic ions should be followed.

Answer to Problem 3.74P
Gold(III) Bromide
Explanation of Solution
An ionic compound is a combination of a cation (positively charged ion) & an anion (negatively charged ion). This combination results in a charge neutralized stable chemical species.
There is a specific pattern to name an ionic compound. Usually, in a formula of an ionic compound, a cation is presented in the right side, while an anion is in the left side.
Using the described rules, the name of the ionic compound can be derived as follows.
Consider AuBr3. The cation is Au3+ (Auric). Au has two cations as Au+ (Aurous) & Au3+ (Auric). So the second rule for cations applies here. So III should be mentioned within brackets. The common name for the metal is Gold.
AuBr3 − Gold(III) + Brom(ine)
Within the brackets, it contains the ending of the anion. That part should be removed to replace by "ide".
Gold(III) + Brom(ide)
Gold(III) Bromide
Gold(III) Bromide is the name of AuBr3, according to the IUPAC (International Union of Pure and Applied Chemistry) rules of ionic compound nomenclature. Generally, AuBr3 also be known as Gold tribromide or Auric bromide.
(f)
Interpretation:
The name of the ionic compound Li2S needs to be determined.
Concept introduction:
In an ionic compound cation is named first, while an anion is named later. As the question contains monoatomic ions, the rules related to the nomenclature of monoatomic ions should be followed.

Answer to Problem 3.74P
Lithium Sulfide.
Explanation of Solution
Ionic compound is a combination of a cation (positively charged ion) and an anion (negatively charged ion). This combination results in a charge neutralized stable chemical species.
There is a specific pattern to name an ionic compound. Usually, in a formula of an ionic compound, a cation is presented in the right side, while an anion is in the left side.
Using the described rules, the name of the ionic compound can be derived as follows.
Consider Li2S. The cation is Li+. The only cation related to Li is Li+. Therefore, 2nd rule of cations is not applied.
Li2S − Lithium + Sulf(ur)
Within the brackets, it contains the ending of the anion. That part should be removed to replace by "ide".
Lithium + Sulf(ide)
Lithium Sulfide
(g)
Interpretation:
The name of the ionic compound SnBr4 needs to be determined.
Concept introduction:
In an ionic compound cation is named first, while an anion is named later. As the question contains monoatomic ions, the rules related to the nomenclature of monoatomic ions should be followed.

Answer to Problem 3.74P
Tin(IV)bromide.
Explanation of Solution
Ionic compound is a combination of a cation (positively charged ion) and an anion (negatively charged ion). This combination results in a charge neutralized stable chemical species.
There is a specific pattern to name an ionic compound. Usually, in a formula of an ionic compound, a cation is presented in the right side, while an anion is in the left side.
Using the described rules, the name of the ionic compound can be derived as follows.
Consider SnBr4. The cation is Sn4+ (Stannic). Sn has two cations as Sn2+ (Stannous) & Sn4+ (Stannic). So the second rule for cations applies here. So IV should be mentioned within brackets. The common name for the metal is Tin.
SnBr4 − Tin(IV) + Brom(ine)
Within the brackets, it contains the ending of the anion. That part should be removed to replace by "ide".
Tin(IV) + Brom(ide)
Tin(IV) Bromide
Tin(IV)Bromide is the name of SnBr4, according to the IUPAC (International Union of Pure and Applied Chemistry) rules of ionic compound nomenclature. Generally, SnBr4 also can be known as Stannic Bromide as Sn4+ ion is known as Stannic ion.
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