Concept explainers
(a)
Interpretation:
The orbital picture of
Concept introduction:
Orbital picture of a molecule can be built up by first determining which orbitals will overlap and interact effectively. These are generally the orbitals from the valence shell of the atoms forming the bonds; mostly s and p orbitals. The orbital that will overlap end-on and the ones that overlap sideways are then determined on the basis of the electron geometry of the atoms. End on overlap leads to
(b)
Interpretation:
The total number of MOs of
Concept introduction:
Sideways interaction of AOs produces MOs of
The number of MOs produced is same as the number of contributing AOs.
(c)
Interpretation:
The orbital energy diagram for CO is to be drawn and the HOMO and LUMO identified.
Concept introduction:
The molecular orbital energy diagram of a molecule is built up by considering the interactions of all the valence shall orbitals from each atom. The total number of MOs produced is the same as the number of interacting AOs.
An end-on overlap of two orbitals produces a pair of MOs of
Interactions between p orbitals produces MOs of two types, one pair with a
The valence electrons of the contributing atoms are then filled in these MOs in increasing order of energy. The MO of highest energy that contains any electrons is called the highest occupied molecular orbital (HOMO), and the empty MO immediately above it is called the lowest unoccupied molecular orbital (LUMO).
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Chapter 3 Solutions
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
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- 4. Assign the following molecules to proper point groups: Pyridine N 1,3,5-triazine N Narrow_forward7. a) Under normal conditions (room temperature & atmospheric pressure) potassium assumes bcc lattice. Atomic radius for 12-coordinate K atom is listed as 235 pm. What is the radius of potassium atom under normal conditions? (3 points) b) Titanium metal crystallyzes in hcp lattice. Under proper conditions nitrogen can be absorbed into the lattice of titanium resulting in an alloy of stoichiometry TiNo.2. Is this compound likely to be a substitutional or an interstitial alloy? (Radius of Ti (12-coordinate) is 147 pm; radius of N atom is 75 pm. (3 points)arrow_forwardcan someone answer the questions and draw out the complete mechanismarrow_forward
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