Mechanism for monobromination of methane that includes initiation, propagation and termination steps should be written.The value of Δ H ° involved in each propagation step and the reaction as a whole should be calculated. The reaction should be thermodynamically compared with other bromination reaction of alkanes . Concept introduction: The monobromination performed with ultraviolet light proceeds via radical chain mechanism. Bromine transforms CH 4 into bromoethane as the major halogenated product with variety of side products due to various possibility of chain termination. It is summarized in the illustration below: The formula to calculate Δ H ° from bond dissociation of reactants and products is as follows: Δ H ° = Sum of D H ° of bonds broken − Sum of D H ° of bonds formed

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Answer 1

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 3, Problem 24P

Interpretation Introduction

Interpretation: Mechanism for monobromination of methane that includes initiation, propagation and termination steps should be written.The value of ΔH° involved in each propagation step and the reaction as a whole should be calculated. The reaction should be thermodynamically compared with other bromination reaction of alkanes.

Concept introduction: The monobromination performed with ultraviolet light proceeds via radical chain mechanism. Bromine transforms CH4 into bromoethane as the major halogenated product with variety of side products due to various possibility of chain termination.

It is summarized in the illustration below:

The formula to calculate ΔH° from bond dissociation of reactants and products is as follows:

ΔH°=Sum of DH° of bonds broken−Sum of DH° of bonds formed

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Answer 2

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 3, Problem 24P

Interpretation Introduction

Interpretation: Mechanism for monobromination of methane that includes initiation, propagation and termination steps should be written.The value of ΔH° involved in each propagation step and the reaction as a whole should be calculated. The reaction should be thermodynamically compared with other bromination reaction of alkanes.

Concept introduction: The monobromination performed with ultraviolet light proceeds via radical chain mechanism. Bromine transforms CH4 into bromoethane as the major halogenated product with variety of side products due to various possibility of chain termination.

It is summarized in the illustration below:

The formula to calculate ΔH° from bond dissociation of reactants and products is as follows:

ΔH°=Sum of DH° of bonds broken−Sum of DH° of bonds formed

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 3

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 3, Problem 24P

Interpretation Introduction

Interpretation: Mechanism for monobromination of methane that includes initiation, propagation and termination steps should be written.The value of ΔH° involved in each propagation step and the reaction as a whole should be calculated. The reaction should be thermodynamically compared with other bromination reaction of alkanes.

Concept introduction: The monobromination performed with ultraviolet light proceeds via radical chain mechanism. Bromine transforms CH4 into bromoethane as the major halogenated product with variety of side products due to various possibility of chain termination.

It is summarized in the illustration below:

The formula to calculate ΔH° from bond dissociation of reactants and products is as follows:

ΔH°=Sum of DH° of bonds broken−Sum of DH° of bonds formed

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 3, Problem 24P

Interpretation Introduction