Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Question
Chapter 3, Problem 19P
To determine
The elevation of the curve at station
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An equal tangent vertical curve is to be constructed between grades of -2.0% (initial) and 1.0% (final). The PVI is at station 11 +
000.000 and at elevation 420 m. Due to a street crossing the roadway, the elevation of the roadway at station 11 + 071.000 must be
at 421.5 m. Design the curve.
A vertical parabolic happy curve underpass has a
grade of -4% followed by a grade of
2% intersecting at Sta. 12+150.60 at
elevation of 124.80 m above sea
level. The change of grade of the sag
curve is restricted to 0.6%.
a. Compute the length of curve.
An equal tangent sag curve is designed with a PVC at station 3+320 and elevation 290m, the PVI at station 3+375 and elevation 288.74m, and the low point is at station 3+365.determine the design speed of the curve.
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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Similar questions
- A plus 5.0 percent grade intersects a minus 3.0 percent grade at station 4 + 10 and at an elevation of 460.60 ft. Given that a PVC station 3+00 is utilized. Determine the length of curve, PVT station, EPVC and EPVT?arrow_forwardA -4% grade line meets another line of +3.2% grade at station 11+ 4O. If a 225-ft parabolic curve connects these grade lines, at what station is the lowest point along the curve located? Your answerarrow_forwardAn equal tangent vertical curve is to be constructed between grades of -2.0% and +1.0 %. The PVI is at station 11 +000.00 and at elevation 420 m. Due a street crossing the roadway, the elevation of the roadway at station 11 +071.00 must be at 421.5 m. Design the curve. (what is the curve length?)arrow_forward
- Question 3 An equal-tangent vertical curve is to be constructed between grades of -2 percent and +1 percent. The PVI is at station 110 + 00 and at elevation 420 ft. Due to a street crossing the roadway, the elevation of the roadway at station 112 + 00 must be at 424.5 ft. Design the curve.arrow_forward4. An equal tangent (sag) vertical curve connects an initial grade of -3% and a final grade of +1% and is designed for 60 mph. The PVI is at station 250+50 and elevation 732 ft. What is the station and elevation of the lowest point on the curve?arrow_forwardA 400-ft equal-tangent sag vertical curve has its PVC at station 78+00 and elevation 800 ft. The initial grade is -4% and the final grade is +2.5%. Determine the station of the lowest point of the curve.arrow_forward
- I need the answer as soon as possiblearrow_forwardQuestion # 5 An existing crest vertical curve which connects +3% and -1% grades is designed for 55 MPH. The curve is to be re-constructed for a 65 MPH design speed. The PVI of the new curve will remain the same as the existing curve but the PVC and PVT will change to accommodate the new curve length. The existing curve's PVT is situated at station 40+00 and the elevation of the existing curve directly below the PVI is 179.22 ft. Stations increase from PVC to PVT. Determine: a. The stations of the new curve at PVC and PVT b. The elevations of the new curve at PVC and PVT c. Determine depth of excavation (d) at PVI station from existing to the new curve. PVC₂ PVC₁ 91 +3% New Curve PVI 92= -1% Elevation 179.22 Station 40+00 PVT₁ PVT2arrow_forwardA tangent section of highway has a -1.0% grade and ends at station 4+75 and elevation 82 ft. It must be connected to another section of highway that has a -1% grade and that begins at station 44+12 and elevation 131.2 ft. The connecting alignment should consist of a sag curve, and be designed for a speed of 50 mi/h. What is the lowest grade possible for the constant-grade section that will complete this alignment?arrow_forward
- A +4.0% grade intersects a -3.0% percent grade at PVI Sta. 222+00 and Elevation 300.00 on a two-lane highway with a design speed of 45 mph. Assume AASHTO Standards. 1. Determine the minimum length for the curve that is designed to meet passing sight distance using K-value method 2. Determine the Station and Elevation of the PVCarrow_forwardAn equal tangent vertical curve is to be constructed between grades of -6.75% (initial) and 4.75% (final). The PVI is at station 12+000.000 and at elevation 319 m. Due to a street crossing the roadway, the elevation of the roadway at station 12+071.00 must be at 324 m. Which of the following most nearly gives the elevation of the PVC in meters? * 335.0 O 330.4 339.0 330.0 348.1arrow_forwardAn equal-tangent curve connects a +1.0% and a -0.5% grade. The PVC is at station 54+24 and the PVI is at station 56+92. Is this curve long enough to provide passing sight distance for a 60-mi/r design speed? Problem 2arrow_forward
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