Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Question
Chapter 3, Problem 58P
To determine
The station of the PT.
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A section of a two-lane highway (3.60 meter lanes) is designed for 120km/h. At one point a vertical curve connects a 2.5% and +1.5 % grade. The PVT of this curve is at station 100+000. It is known that a horizontal curve starts (has PC) 89.6 meters before the vertical curve's PVC. If the super elevation of the horizontal curve is 0.08 and the central angle is 38 degrees, what is the station of the PT?
A horizontal curve is being designed for a new two-lane highway (3.6-m lanes).
The PI is at station 7 + 640, the design speed is 105 km/h, and a maximum superelevation of
0.08 m/m is to be used. If the central angle of the curve is 35 degrees, design a curve for the
highway by computing the radius and stationing of the PC and PT.
A section of a two-lane highway (12-ft lanes) is designed for 75 mph. At one point, a vertical curve connects a -2.5% and +1.5% grade. The VPT of this curve is at station 25+00. It is known that a horizontal curve starts (has PC) 292 ft before the vertical curve VPC. If the superelevation of the horizontal curve is 0.08 and the central angle is 38 degrees, what is the station of the PT?
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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- Q6. To help improve the safety of at-grade intersection of two roads, the intersection is being redesigned so that the E-W road will pass underneath the N-S road. Currently the vertical alignment of the E-W road consists of a crest vertical curve joining a 4% upgrade to a 3% downgrade. The existing vertical curve is 138 m long, the PVC of this curve is at station 14+47, and the elevation of the PVC is 477 m. The centerline of the N-S road is at station 15+45. Your job is to find the shortest vertical curve that provides 6.0 m of clearance between the new E-W road and the N-S road.arrow_forwardsolve on paperarrow_forwardA horizontal curve is being designed for a new four-lane roadway with 11-ft lanes. The PT is located at station 1050+20, the design speed is 45 mph and maximum superelevation of 4%. If the central angle of the curve is 30 degrees, what is the radius of the curve and location of the PC and PI?arrow_forward
- 3.48 A horizontal curve is being designed for a new two-lane highway (12-ft lanes). The PI is at station 250 + 50, the design speed is 65 mi/h, and a maximum superelevation of 0.07 ft/ft is to be used. If the central angle of the curve is 38 degrees, design a curve for the highway by computing the radius and stationing of the PC and PT. 3.49 You are nalarrow_forwardA horizontal Curve is designed for a two lane mountainous terrain. The following data are known. intersection angle: 40 degrees tangent length: 436.76 ft Station on PI: 2700+10.65 fs=0.12 e=0.08 Find the following Design speed Station of the PC Station of the PT Deflection Angle and chord length to the first even 100 ft stationarrow_forward3.35 A horizontal curve on a two-lane highway (10-ft lanes) is designed for 50 mi/h with a 6% superelevation. The central angle of the curve is 35 degrees and the PI is at station 482 + 72. What is the station of the PT and how many feet have to be cleared from the lane's shoulder edge to provide adequate stopping sight distance?arrow_forward
- 2. A vertical parbolic curve was design in order to have a clear sight distance of 120 m. The grade lines intersect at Sta 9+000 at elev 160.50. The curve was design such that when the height of the drivers eye is 1.50 m above the payment it would just see an object whose height is 0.10 m above the pavement. Determine the max speed that a car could travel grade of 5% and a downgrade of -3%.arrow_forwardBoth vertical and horizontal curves on the same section of a highway are designed at the same speed. A vertical sag-curve on this highway connects G1=-7% and G2=? % grades and is 300 m long. If a horizontal curve on this highway is on a two-lane section with 3.6-m lanes, has a central angle of 43 degrees and a superelevation of 4%,arrow_forwardA sag curve connects a -1.5 percent grade with a +2.5 percent grade on a rural arterial highway. The criterion selected for design is the minimum stopping sight distance, and the design speed of the highway is 70 mph. Assume the perception-reaction time of 2.5 seconds and a deceleration rate of 11.2 ft./sec^2. a. Determine the length of the curve. b. Compute the elevation of the curve at PVC and PVT if the grades intersect at station (475 + 00) at an elevation of 300 ft.arrow_forward
- Q: A horizontal curve is being designed through mountainous terrain for a four- ane with lanes that are 3 m wide. The central angle is known to be 40 degrees, the tangent distance is 155m, and the stationing of the tangent intersection (PI) 'is 8 + 23. Under specified conditions and vehicle speed, the roadway surface is determined to have a coefficient of side friction of 0.08, and the curve's superelevation is 0.09. what is the stationing of the PC and PT and what is the safe vehicle speed?arrow_forward1. A vertical parabolic summit curve was designed in order to have a clear sight distance of 120m. The grade lines intersect a Station 9 + 000 at elevation 160.50m. The curve was so designed such that when the height of the driver's eye to 1.50m above the pavement would just see an object whose height is 0.10m above the pavement. Determine the max. speed that a car could travel along this curve. The grade lines has an upward grade of 5% and a downward grade of -3%.arrow_forwardAn equal-tangent crest vertical curve is designed with a PVI at station 110 + 00 (elevation 927.2 ft) and a PVC at station 107 + 43.3 (elevation 921.55 ft). If the high point is at station 110 + 75.5, what is the design speed of the curve?arrow_forward
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