Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Question
Chapter 3, Problem 48P
To determine
The radius of the curve and the stationing of
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A horizontal curve is being designed for a new two-lane highway (3.6-m lanes).
The PI is at station 7 + 640, the design speed is 105 km/h, and a maximum superelevation of
0.08 m/m is to be used. If the central angle of the curve is 35 degrees, design a curve for the
highway by computing the radius and stationing of the PC and PT.
A horizontal curve is being designed for a new two-lane highway (12-ft
lanes). The PC is at station 150+50, design speed is 55 mi/h, and a superelevation of 0.08 fuft
is to be used. If the central angle of the curve is 40 degrees, design a curve for the highway by
computing the minimum radius and stationing of the PI and PT??
A horizontal curve is being designed for a new four-lane roadway with 11-ft lanes. The PT
is located at station 1050+20, the design speed is 45 mph and maximum superelevation of
4%. If the central angle of the curve is 30 degrees, what is the radius of the curve and
location of the PC and PI?
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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- Design a horizontal curve for the highway by computing the radius and stationing of PC and PT using the following data, # of lanes = 2 Width per lane = 12 ft Pl is at station 120+20 Design speed is 60 mi/h Superelevation = 0.06 ft/ft Central angle of the curve = 37 degreesarrow_forward3.48 A horizontal curve is being designed for a new two-lane highway (12-ft lanes). The PI is at station 250 + 50, the design speed is 65 mi/h, and a maximum superelevation of 0.07 ft/ft is to be used. If the central angle of the curve is 38 degrees, design a curve for the highway by computing the radius and stationing of the PC and PT. 3.49 You are nalarrow_forwardA section of a two-lane, two-way highway (2 @ 3.5 m) is to be designed with a circular curve. Sta. Pl at 200 + 100.000 Design speed = 60 kph Intersection angle = 40 degrees Rate of change of acceleration: 0.5 m/sec2arrow_forward
- Problem 2. A horizontal curve is being designed for a two-lane highway (12-ft lanes). The PC is at station 1200 + 50, the design speed is 70 mph, and a design superelevation of 0.08 ft/ft is to be used. Central angle of the curve is 40 degrees. (1) What is the min radius (measured to the centerline of the inside-most lane)? (2) Use the min value in your design, determine the station of PT. A = 40' e = 0.08 V = 70 mph PC = 1200150 1 +3 3131(6(vtoner) =951.88 -Simple Circular curves - reverse curtes- compound curves - spr e bus of Sogements Options curves fs=0.08 9=32.174H/S²arrow_forward12. Find the minimum length of curve for the following scenarios. Entry Grade Exit Grade Design Speed Reaction Time A 3% 8% 45 mi/hr 2.5 s В -4% 2% 65 mi/hr 2.5 s 0 % -3% 70 mi/hr 2.5 sarrow_forwardCreate a circular curve using this data with a section of a two lane, two highwayarrow_forward
- The design speed for a two-lane highway (lane width=12 ft.) is 60 mph. The localjurisdiction governs 8% superelevation. The central angel of the curve is 40 degrees. The PI station is at 452+50.What is the curve radius to the travel path (R)? What is the curve radius (R)? What is the curve length (L)? What isthe station of PC? What is the station of PT? What is the SSD? How many feet must be cleared from the lane'sshoulder edge to provide adequate stopping sight distance?arrow_forwardA horizontal Curve is designed for a two lane mountainous terrain. The following data are known. intersection angle: 40 degrees tangent length: 436.76 ft Station on PI: 2700+10.65 fs=0.12 e=0.08 Find the following Design speed Station of the PC Station of the PT Deflection Angle and chord length to the first even 100 ft stationarrow_forwardQ: A horizontal curve is being designed through mountainous terrain for a four- ane with lanes that are 3 m wide. The central angle is known to be 40 degrees, the tangent distance is 155m, and the stationing of the tangent intersection (PI) 'is 8 + 23. Under specified conditions and vehicle speed, the roadway surface is determined to have a coefficient of side friction of 0.08, and the curve's superelevation is 0.09. what is the stationing of the PC and PT and what is the safe vehicle speed?arrow_forward
- solve on paperarrow_forwardA vertical curve is going to be designed to join a 0% grade with a +5% grade at a section of a highway. The station and elevation of the PVC point are 5+00 and 12 ft, respectively. Assuming AASHTO design standard values for perception-reaction time, deceleration rate for braking, and driver's eye and object heights, determine the following: 1. The min length of the curve if the design speed is 65 mi/h. 2. The station and elevation of the PVT. 3. The station and elevation of the high or low point. 4. The elevation of the point at station 6+50.arrow_forwardDesign a vertical curve (i.e., Determine length of the curve as well as station and elevation of the vertical curve's PVC and PVT) with the given PVI (station and elevation given the figure below) to go through a future intersection location at the point at which the vertical curve is flat. Report the vertical curve's design speed to the nearest 5 miles per hour. PVC Future Intersection Station = 100+00 G1 = -2.6% PVT PVI G2 = 1.0% Station = 99+00 Elevation = 228 ft %3|arrow_forward
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