Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Question
Chapter 3, Problem 20P
To determine
The elevation and stationing of the low pointPVI, and PVT.
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A 850-ft equal-tangent creat vertical cuve has its PVC at station 102+00 and elevation 1000 ft. The initial grade is 3.5% and the final grade is -3%. Determine the station of the highest point of the curve
A +4.0% grade intersects a -3.0% percent grade at PVI Sta. 222+00 and
two-lane highway with a design speed of 45 mph. Assume AASHTO Standards.
1. Determine the minimum length for the curve that is designed to meet passing sight
distance using K-value method
2. Determine the Station and Elevation of the PVC
Duoblem 1
A 500-ft-long equal-tangent crest vertical curve connects tangents that intersect at station 340 + 00 and elevation 1322 ft. The initial grade is +4.0% and the final grade is -2.5%. Determine the elevation and stationing of the high point, PVC, and PVT.
Solve this problem using parabolic equation and offset method.
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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Similar questions
- A 1400-ft-long sag vertical curve (equal tangent) has a PVC at station 115 + 00 and elevation 750 ft. The initial grade is -3.5% and the final grade is +6.5%. Determine the elevation and stationing of the low point, PVI, and PVT.arrow_forwardA 532m equal tangent crest vertical curve has PVC at Sta 19+284 and at elevation 181m. The initial grade is 3.02% and the final grade is -4.37%. Determine the elevation (m) of PVI.arrow_forwardA +4.0% grade intersects a -3.0% percent grade at PVI Sta. 222+00 and Elevation 300.00 on a two-lane highway with a design speed of 45 mph. Assume AASHTO Standards. 1. Determine the minimum length for the curve that is designed to meet passing sight distance using K-value method 2. Determine the Station and Elevation of the PVCarrow_forward
- A 400-ft equal-tangent sag vertical curve has its PVC at station 78+00 and elevation 800 ft. The initial grade is -4% and the final grade is +2.5%. Determine the station of the lowest point of the curve.arrow_forwardQ3/ A vertical curve below has a lower point (A) which exists at station (55+50) with elevation (1291.2 m). the back grade of (-8%) meet the forward grade of (+7.8%) at (PVI) station (54+00) with elevation (1281.5 m). determine the length of the curve with the stations of (PVC) and (PVT)? PVT PVC g₁=(-6%) PVI g₂=(+5.8%)arrow_forwardAn equal tangent sag curve is designed with a PVC at station 3+320 and elevation 290m, the PVI at station 3+375 and elevation 288.74m, and the low point is at station 3+365.determine the design speed of the curve.arrow_forward
- PLEASE PROVIDE COMPLETE SOLUTION THANKSarrow_forwardHighway engineering: A 520-ft–long equal-tangent crest vertical curve connects tangents that intersect at station 340 + 00 and elevation 1325 ft. The initial grade is +4.0% and the final grade is -2.5%. Determine the elevation and stationing of the high point, PVC, and PVT.arrow_forwardA -3% grade meets a +5% grade near an underpass. In order to maintain the minimum clearance allowed under the bridge and at the same time introduce a vertical transition curve in the grade line, it is necessary to use a curve that lies 200 m on one side of the vertex of the straight grade and 100 m on the other. The station of PC is 10 + 000 and its elevation is 228 m. Determine the stationing of the lowest point of the curve. A 10+211 B. 10+200 C. 10+106 D. 10+207arrow_forward
- An equal tangent vertical curve is to be constructed between grades of -2.0% (initial) and 1.0% (final). The PVI is at station 11 + 000.000 and at elevation 420 m. Due to a street crossing the roadway, the elevation of the roadway at station 11 + 071.000 must be at 421.5 m. Design the curve.arrow_forwardA crest vertical curve (equal tangent) has PVI at station 210+00 and elevation 420.75 ft. The initial grade is 2.5% and the final grade is -4%. The length of the curve is 950 ft. Determine the following, 1. Stationing of the high point, PVC, and PVT. 2. Elevation at station 212+00, PVC, high point, and PVT.arrow_forwardAn equal-tangent sag vertical curve is designed for 100 kph. The lowest point is at elevation 308.0 m. The initial grade is -2% and the final grade is +1%. What is the elevation of the PVC?arrow_forward
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