Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
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Chapter 3, Problem 15P
To determine
Whether the curve is long enough to provide passing sight distance for a
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A +3.00% grade intersects a -2.40% at station 46+70.00 and elevation 853.48 ft. A 400.00 ft curve will be used to connect the two grades. Compute Station and elevation for the curve's endpoints.
An equal-tangent curve connects a +1.0% and a -0.5% grade. The PVC is at station 54+24 and the
PVI is at station 56+92. Is this curve long enough to provide passing sight distance for a 60-mi/r
design speed?
Problem 2
An overpass is being built over the PVI of an existing equal-tangent curve. The curve has a 70-
mi/h design speed and G1 = -5%, G2= +3%. Determine the minimum necessary clearance height
of the overpass and the resultant elevation of the bottom of the overpass over the PVI. (Ignore the
cross-sectional width of the overpass.)
An equal-tangent crest curve connects a +1.0%and a -0.5% grade. The PVC is at
station 54 + 24 and the PVI is at station 56 + 92. Is this curve long enough to provide
passing sight distance for a 60-mi/h design speed? '
Chapter 3 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- An equal-tangent crest vertical curve is designed with a PVI at station 110 + 00 (elevation 927.2 ft) and a PVC at station 107 + 43.3 (elevation 921.55 ft). If the high point is at station 110 + 75.5, what is the design speed of the curve?arrow_forwardAn equal-tangent sag vertical curve is designed with the PVC at station 109 + 00 and elevation 950 ft, the PVI at station 110 + 77 and elevation 947.34 ft, and the low point at station 110 + 50. Determine the design speed of the curve.arrow_forwardAn equal-tangent vertical curve connects an initial grade of -4% and a final gradeof +1% and is designed for 60 mile/hour. The PVI is at station 250+50 and elevation of 732 ft. What is thestation and elevation of the lowest point on the curve?arrow_forward
- Please correct answerarrow_forwardAn equal-tangent sag vertical curve is designed for 45 mi/h. The low point is 237 ft from the PVC at station 112 + 37 and the final offset at the PVT is 19.355 ft. If the PVC is at station 110 + 00, what is the elevation difference between the PVT and a point on the curve at station 111 + 00?arrow_forwardA 3.5% grade passing at station 49+45.00 at an elevation of 174.83 ft meets a -5.5% grade passing at station 49+55.00 at an elevation of 174.73 ft. Determine the station and elevation of the point of intersection of the two grades as well as the length of the curve, L, if the highest point on the curve must lie at station 48+61.11arrow_forward
- 1. (Crest Vertical Curve) A vertical curve is designed for 55 mi/h and has an initial grade of +2.5% and a final grade of -1.0%. The PVT is at station 114 + 25. It is known that a point on the curve at station 112 + 75 is at elevation 240 ft. What is the stationing and elevation of the PVC? What is the stationing and elevation of the high point on the curve?arrow_forwardA crest vertical curve (equal tangent) has PVI at station 210+00 and elevation 420.75 ft. The initial grade is 2.5% and the final grade is -4%. The length of the curve is 950 ft. Determine the following, 1. Stationing of the high point, PVC, and PVT. 2. Elevation at station 212+00, PVC, high point, and PVT.arrow_forwardAn equal-tangent vertical curve is to be constructed between grades of -2.0% (initial) and +1.0% (final). The PVI is at station 110 + 00 and at elevation 420 ft. Due to a street crossing the roadway, the elevation of the roadway at station 112 + 00 must be at 424.5 ft. Design the curve.arrow_forward
- 2. There is an equal-tangent vertical curve, which is 1,115 ft long. It connects an initial grade of +2.5% and a final grade of -1.0%. PVI of the vertical curve is at station 110 + 00 with its elevation of 1,005 ft. Please determine following. a. PVC station b. PVC elevation C. PVT station d. PVT elevation e. The station where the highest elevation is located f. The highest elevation on the road g. The stations where the road elevation is 995 feet. Crest Vertical Curve PVI = 110+00 sta Design Speed: 70 mph Yev= 1,005' PVI Highest elevation PVI 2.5% -2.0% PVC PVT Elevation = 995 ft L=1,115 ftarrow_forward4. An equal tangent (sag) vertical curve connects an initial grade of -3% and a final grade of +1% and is designed for 60 mph. The PVI is at station 250+50 and elevation 732 ft. What is the station and elevation of the lowest point on the curve?arrow_forwardAn SVC connects a -4% grade to a +4% grade. The curve goes under a pedestrian bridge at PVI. The vertical clearance under the bridge should be 15 ft and the required sight distance is 984 ft. The height of the driver's eye is 6 ft, and the assumed hazardous object is 1.5 ft tall. What should be the length of the curve? Assume S > L.arrow_forward
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