Chapter 27.1, Problem 15PP

To determine

To Identify:The metal.

Explanation of Solution

Introduction:

Photoelectric effect equation:

  $E=\frac{hc}{{\lambda }_o}+K.E$

Here, E is the energy of the incident light, h is the Planck’s constant, c is the speed of light, ${\lambda }_o$ is the longest wavelength required to reject electron (threshold wavelength) and K.E. is the kinetic energy of the ejected electron.

As per question, electron is ejected from the metal when the longest wavelength of light, ${\lambda }_o=273\text{nm}$ is incident upon it. From Table 1, the most likely metal is Silver. The threshold wavelength of Silver is 270 nm.