Chapter 27, Problem 43A

To determine

To Find: The momentum of a photon of violet light.

Answer to Problem 43A

  $1.65\times {10}^{-27}\text{N}\cdot \text{s}$

Explanation of Solution

Given data:

Wavelength of violet light, $\lambda =4\times {10}^2\text{nm}$

Formula used:

The momentum of a photon

  $p=\frac{E}{c}=\frac{hc}{\lambda c}=\frac{h}{\lambda }$

Calculation:

  $\begin{array}{l}p=\frac{h}{\lambda }\\ p=\frac{6.6\times {10}^{-34}\text{J}\cdot \text{s}}{4\times {10}^2\times {10}^{-9}\text{m}}\\ p=1.65\times {10}^{-27}\text{N}\cdot \text{s}\end{array}$

Conclusion:

The momentum each photon of violet light is $1.65\times {10}^{-27}\text{N}\cdot \text{s}$ .