Chapter 27.1, Problem 23SSC

To determine

To Calculate: Energy of electron being ejected from the bone when X-ray is incident on it.

Answer to Problem 23SSC

  $62000\text{eV}$

Explanation of Solution

Given data:

Wavelength of the X-ray, ${\lambda }_{\text{x-ray}}=0.02\text{nm}$

Work function of the bone is negligible in comparison to X-ray energy.

Formula used:

Energy of the incident light:

  $E=\frac{1240\text{eV}\cdot \text{nm}}{\lambda }$

Here, $\lambda$ is the wavelength of the incident light.

Calculation:

Energy of the light:

  $\begin{array}{l}E=\frac{1240\text{eV}\cdot \text{nm}}{\lambda }\\ E=\frac{1240\text{eV}\cdot \text{nm}}{0.02\text{nm}}\\ E=62000\text{eV}\end{array}$

As the work function of the bone is negligible, the energy of the incident X-ray would be equal to kinetic energy of the ejected electron.

Conclusion:

So, the energy of the ejected photon is $62000\text{eV}\text{.}$