Chapter 27.1, Problem 2PP

To determine

To Find: Wavelength of photon.

Answer to Problem 2PP

  $610.83\text{ nm}$

Explanation of Solution

Given data:

Energy of photon is $E=2.0\text{3 eV}$ .

Formula Used:

Energy of the photon can be obtained by:

  $E=\frac{1240\text{eV}\cdot \text{nm}}{\lambda }$

Where, $\lambda$ is the wavelength.

Calculation:

  $\begin{array}{l}E=\frac{1240\text{eV}\cdot \text{nm}}{\lambda }\\ \Rightarrow \lambda =\frac{1240\text{eV}\cdot \text{nm}}{E}\\ \lambda =\frac{1240\text{eV}\cdot \text{nm}}{2.03\text{eV}}\\ \lambda =610.83\text{ nm}\end{array}$

Conclusion:

The wavelength of the photon is $610.83\text{ nm}$ .