Introduction to General, Organic and Biochemistry
12th Edition
ISBN: 9780357119303
Author: Bettelheim, Frederick A., Brown, William H., Campbell, Mary K., FARRELL, Shawn O., Torres, Omar
Publisher: Cengage Learning
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Chapter 27, Problem 75P
Interpretation Introduction
Interpretation:
The reason of energy yield change for carbohydrate and fats should be explained.
Concept Introduction:
Fats are the organic compounds with long hydrophobic carbon chain and small hydrophilic −COOH part. Carbohydrates are the
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Chapter 27 Solutions
Introduction to General, Organic and Biochemistry
Ch. 27.1 - Prob. 27.1QCCh. 27.2 - Prob. 27.2QCCh. 27.3 - Prob. 27.3QCCh. 27.4 - Prob. 27.4QCCh. 27.5 - Prob. 27.5QCCh. 27.6 - Prob. 27.6QCCh. 27.7 - Prob. 27.7QCCh. 27.8 - Prob. 27.8QCCh. 27.9 - Prob. 27.9QCCh. 27 - Prob. 1P
Ch. 27 - What are the products of lipase-catalyzed...Ch. 27 - What is the main use of amino acids in the body?Ch. 27 - Prob. 4PCh. 27 - Prob. 5PCh. 27 - Prob. 6PCh. 27 - Prob. 7PCh. 27 - Prob. 8PCh. 27 - Prob. 9PCh. 27 - Prob. 10PCh. 27 - Prob. 11PCh. 27 - Prob. 12PCh. 27 - Prob. 13PCh. 27 - Prob. 14PCh. 27 - Prob. 15PCh. 27 - Prob. 16PCh. 27 - Prob. 17PCh. 27 - Prob. 18PCh. 27 - Prob. 19PCh. 27 - Prob. 20PCh. 27 - Two enzymes participating in ß-oxidation have the...Ch. 27 - Prob. 22PCh. 27 - Prob. 23PCh. 27 - Is the ß -oxidation of fatty acid (without the...Ch. 27 - Calculate the number of ATP molecules obtained in...Ch. 27 - Prob. 26PCh. 27 - Prob. 27PCh. 27 - Prob. 28PCh. 27 - Prob. 29PCh. 27 - Prob. 30PCh. 27 - Prob. 31PCh. 27 - Prob. 32PCh. 27 - Prob. 33PCh. 27 - Ammonia, NH3, and ammonium ion, NH+4are both...Ch. 27 - Prob. 35PCh. 27 - Prob. 36PCh. 27 - Prob. 37PCh. 27 - Prob. 38PCh. 27 - 28-39 The metabolism of the carbon skeleton of...Ch. 27 - Prob. 40PCh. 27 - Prob. 41PCh. 27 - Prob. 42PCh. 27 - (Chemical Connections 27B ) Does gastric bypass...Ch. 27 - Prob. 44PCh. 27 - Prob. 45PCh. 27 - Prob. 46PCh. 27 - Prob. 47PCh. 27 - Prob. 48PCh. 27 - Prob. 49PCh. 27 - Prob. 50PCh. 27 - Prob. 51PCh. 27 - Prob. 52PCh. 27 - Prob. 53PCh. 27 - Write the products of the transamination reaction...Ch. 27 - Prob. 55PCh. 27 - Prob. 56PCh. 27 - Prob. 57PCh. 27 - Prob. 58PCh. 27 - Prob. 59PCh. 27 - Prob. 60PCh. 27 - Prob. 61PCh. 27 - Prob. 62PCh. 27 - Prob. 63PCh. 27 - Prob. 64PCh. 27 - Prob. 65PCh. 27 - Prob. 66PCh. 27 - Prob. 67PCh. 27 - Prob. 68PCh. 27 - Prob. 69PCh. 27 - Prob. 70PCh. 27 - Prob. 71PCh. 27 - Prob. 72PCh. 27 - Prob. 73PCh. 27 - Prob. 74PCh. 27 - Prob. 75PCh. 27 - Many soft drinks contain citric acid to add...Ch. 27 - Prob. 77PCh. 27 - Prob. 78PCh. 27 - Prob. 79PCh. 27 - Prob. 80P
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- Don't used Ai solutionarrow_forward5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3arrow_forwardShow work. don't give Ai generated solution. How many carbons and hydrogens are in the structure?arrow_forward
- 13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…arrow_forwardBr. COOH Br, FCH COOH E FeBr ASOCI B NH (CH,CO),OD Br₂ 2 C alcKOHarrow_forwardFind A to F (all)arrow_forward
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