To draw: A diagram including exons and introns of a gene that encodes both membrane-bound and soluble forms of a protein. Introduction: In eukaryotes, transcription occurs in the nucleus, and pre-mRNA is synthesized. This pre-mRNA is further modified before translation in the cytoplasm. This is known as RNA processing. It includes the modification of mRNA ends and RNA splicing. During RNA splicing, the non-coding regions, that is introns, are excised from the RNA molecules, and the coding regions are joined.

Question

The beta-lactamase hydrolyzes the lactam-ring in penicillin. Describe the mechanism of hydrolysis, insuring to include the involvement of S, D, & K in the reaction sequence. Please help

Answer 1

Question

Chapter 26, Problem 22E

Summary Introduction

To draw: A diagram including exons and introns of a gene that encodes both membrane-bound and soluble forms of a protein.

Introduction: In eukaryotes, transcription occurs in the nucleus, and pre-mRNA is synthesized. This pre-mRNA is further modified before translation in the cytoplasm. This is known as RNA processing. It includes the modification of mRNA ends and RNA splicing. During RNA splicing, the non-coding regions, that is introns, are excised from the RNA molecules, and the coding regions are joined.

Summary Introduction

To explain: How one gene can code for two different forms of a protein.

Introduction: In eukaryotes, transcription occurs in the nucleus, and pre-mRNA is synthesized. This pre-mRNA is further modified before translation in the cytoplasm. This is known as RNA processing. It includes the modification of mRNA ends and RNA splicing. During RNA splicing, the non-coding regions, that is introns, are excised from the RNA molecules, and the coding regions are joined. Some genes undergo alternative splicing, which leads to the production of two or more different mRNAs from the same primary transcript.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

The beta-lactamase hydrolyzes the lactam-ring in penicillin. Describe the mechanism of hydrolysis, insuring to include the involvement of S, D, & K in the reaction sequence. Please help

To map the active site of beta-lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine. Why doesn't D in this hexapeptide not participate in the hydrolysis of the beta-lactam ring even though S, K, and D are involved in the catalyst?

To map the active site of -lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine. Using the experimental results described above derive the primary sequence of the active site hexapeptide. Please help!