EBK MANUFACTURING ENGINEERING & TECHNOL
7th Edition
ISBN: 8220100793431
Author: KALPAKJIAN
Publisher: PEARSON
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Chapter 25, Problem 41QTP
Estimate the optimum cutting speed in Problem 25.40 for maximum production.
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Students have asked these similar questions
An external turning operation is performed on a hollow workpiece of 200 mm external
diameter and 100 mm inner diameter, at 40 m/min cutting speed, 2 mm depth of cut
and 0.20 mm/rev feed. Calculate:
The rotational speed for this workpiece.
The machining time needed for a length of 250 mm.
The material removal rate used.
The parting-off time needed if the cross feed is 0.1 mm/rev.
The expected tool life if the constants in Taylor Formula are n=0.23 and C= 240.
The maximum number of work pieces that could be produced under the given
cutting conditions, before the tool needs re-sharpening.
The orthogonal cutting of steel is done with 10° rake tool with a depth of cut of 4mm
feed rate of 0.4mm/rev. The cutting speed is 200m/min. The chip thickness ratio is
0.35. The vertical cutting force is 1200N and the horizontal cutting force is 700N.
Calculate from the Merchant's theory, the various work done in metal cutting and shear
stress.
* ordiogonal cutting of material the feed force is 80 kg and cuutting force is 150 kg. Calculate the
following:
1. Compression and shear forces on shear plane.
2. Coefficient of friction of the chip on the tool face. Take chip thickness ratio as 0.3 and rake angle
as 8.
Chapter 25 Solutions
EBK MANUFACTURING ENGINEERING & TECHNOL
Ch. 25 - Describe the distinctive features of machining...Ch. 25 - Explain how the tooling system in a machining...Ch. 25 - Explain the trends in materials used for...Ch. 25 - Is there any difference between chatter and...Ch. 25 - What are the differences between forced and...Ch. 25 - Explain the importance of foundations in...Ch. 25 - Explain why automated pallet changers and...Ch. 25 - What types of materials are machine-tool bases...Ch. 25 - What is meant by the modular construction of...Ch. 25 - What is a hexapod? What are its advantages?
Ch. 25 - What factors contribute to costs in machining...Ch. 25 - List the reasons that temperature is important in...Ch. 25 - Explain the technical and economic factors that...Ch. 25 - Spindle speeds in machining centers vary over a...Ch. 25 - Explain the importance of stiffness and damping of...Ch. 25 - Are there machining operations described in...Ch. 25 - How important is the control of cutting-fluid...Ch. 25 - Review Fig. 25.10 on modular machining centers,...Ch. 25 - Prob. 19QLPCh. 25 - Describe the adverse effects of vibration and...Ch. 25 - Describe some specific situations in which thermal...Ch. 25 - Prob. 22QLPCh. 25 - Prob. 23QLPCh. 25 - Prob. 24QLPCh. 25 - List the parameters that influence the temperature...Ch. 25 - List and explain factors that contribute to poor...Ch. 25 - Prob. 27QLPCh. 25 - Prob. 28QLPCh. 25 - Describe types and sizes of workpieces that would...Ch. 25 - Prob. 30QLPCh. 25 - Explain the advantages and disadvantages of...Ch. 25 - What are the advantages and disadvantages of (a)...Ch. 25 - What would be the advantages and limitations of...Ch. 25 - Explain how you would go about reducing each of...Ch. 25 - Describe workpieces that would not be suitable for...Ch. 25 - Give examples of forced vibration or self-excited...Ch. 25 - A machining-center spindle and tool extend 10 in....Ch. 25 - Using the data given in the example, estimate the...Ch. 25 - A machining-center spindle and tool extend 12 in....Ch. 25 - In the production of a machined valve, the labor...Ch. 25 - Estimate the optimum cutting speed in Problem...Ch. 25 - Prob. 42QTPCh. 25 - If you were the chief engineer in charge of the...Ch. 25 - Prob. 45SDPCh. 25 - Make a list of components of machine tools that...Ch. 25 - The cost of machining and turning centers is...Ch. 25 - Prob. 49SDPCh. 25 - Describe your thoughts on whether or not it is...Ch. 25 - Prob. 51SDPCh. 25 - Prob. 53SDP
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- Example 3.18 A low carbon steel bar of 147 mm diameter with length of 630 mm is being turned with uncoated carbide insert. The observed tool life are 24 and 12 for cutting velocities of 90 m/min and 120 m/min respectively. The feed and depth of cut are 0.2 mm./rev and 2 mm respectively. Use the unmachined to calculate the cutting velocity (i) When tool life is 20 min. the cutting velocity in m/min is (a) 87 (b) 97 (c) 107 (d) 114 (ii) Neglect over travel or approach of the tool. When tool life is 20 min, the machining time in remain for a single pass is (a) 5 (b) 10 (c) 15 (d) 20arrow_forwardAssuming that the coefficient of friction is 0.25, calculate the maximum depth of cut forturning a hard aluminium alloy on a 15-kW lathe (with a mechanical efficieny of 80%) at awidth of cut of 6 mm, rake angle of 0˚, and a cutting speed of 90 m/min, shear strength of 150 MPa.arrow_forwardIn orthogonal turning of a low carbon steel bar of diameter 150 mm with uncoated carbide tool. the cutting velocity is 90 m/min The feed is 0.24 mm/rev and the depth of cut is 2 mm. The chip thickness obtained is 0.48 mm If the orthogonal rake angle is zero and the principal cutting edge angle is 90° Calculate the shear angle in degree.arrow_forward
- A steel rod 250 mm long and 200 mm in diameter is being reduced to 190 mm in diameter all over its length in one travel. The machine spindle rotates at 500 rpm, whereas the tool is moving at an axial feed of 0.5 mm/rev; calculate the following: Material removal rate (mm3/min) Consumed gross power in Nm/s if cutting force is 477.5N and mechanical efficiency is 90% Cutting time plzz complete in 30 minutesarrow_forwardIn turning of stales steel alloy, 1100 mm length and 400 mm diameter, the Feed was 0.35 mm/rev, and depth of cut = 2.5 mm. The tool used in this cutting is cemented carbide tool where Taylor tool life parameters are n = 0.24 and C = 450 (tool life (min) and cutting speed (m/min). Compute the cutting speed that will allow the tool life to be 10% longer than the machining time for this part.arrow_forwardOnly answer question 2arrow_forward
- 3. On an upright drilling machine, a 20 mm diameter hole is to be produced in a plate of SAEE112 steel of 30 mm thickness. The cutting speed selected is 10 m/min, and the cutting torque measured is 20 N.m. Calculate the spindle speed, the depth of cut, the main cutting force, and the cutting power.arrow_forwardAn orthogonal cutting operation is being carried out under the following conditions: depth of cut, to = 0.1 mm, rake angle, a = 10°, Cutting force, Fc =1500 N, and Thrust force, Ft = 800 N. Calculate the shear force.arrow_forward, Given that cutting speed 9 m/min, the return time to cutting time ratio is 1:2 the feed rate 0.3 mm/stroke, the clearance at each of cut 25 mm and that the plate is fixed 700 mm side along the direction of toll travel, the time required for finishing one flat surface of a plate of size 700 x300 mm in a shaper, will bearrow_forward
- . What are parameters of cutting process? mention it with units.arrow_forward6arrow_forwardNote: Read the question carefully and give me right solutions according to the question. In orthogonal cutting of steel tube of 150 mm diameter and 2 mm thick, the cutting force was 130 kg and feed force was 35 kg for chip thickness of 0.3mm. The orthogonal cut was taken at 60 meter per minute with a feed of 0.14 mm/rev. If the back rack angle of the cutting tool was - 8 o (minus 8 degree), then calculate the shear strain and strain energy per unit volume.arrow_forward
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