Chapter 25, Problem 32P

To determine

The magnification of the astronomical telescope.

Answer to Problem 32P

Solution:

$-\text{22}.\text{42}$

Explanation of Solution

Given:

$L=\text{82cm}$

$f_o=78.5cm$

Formula used:

$M=-\frac{f_o}{f_e}$

$L=f_o+f_e$

Calculation:

Length of the telescope is given by,

$\begin{array}{l}L=f_o+f_e\\ f_e=L-f_o\\ f_e=82-78.5\\ f_e=3.5\text{cm}\end{array}$

Magnification of astronomical telescope is given by,

$\begin{array}{l}M=-\frac{78.5}{3.5}\\ M=-22.42\text{X}\end{array}$