Chapter 25, Problem 28P

To determine

(a) To determine:

The magnification of the astronomical telescope.

Answer to Problem 28P

Solution:

29.281X

Explanation of Solution

Given:

$\begin{array}{l}{f}_o=82cm\\ f_e=2.8cm\end{array}$

Formula used:

$M=-\frac{f_o}{f_e}$

$L=f_o+f_e$

Calculation:

Magnification of astronomical telescope is given by,

$\begin{array}{l}M=-\frac{f_o}{f_e}\\ M=-\frac{82}{2.8}\\ M=-29.28\text{X}\end{array}$

To determine

(b) To determine:

The length of the telescope

Answer to Problem 28P

Solution:

$\text{84}.\text{8cm}$

Explanation of Solution

Calculation:

Length of the telescope is given by,

$\begin{array}{l}L=f_o+f_e\\ L=82+2.8\\ L=84.8\text{cm}\end{array}$