a.
To describe how the graph of the function can be obtained from the graph of
a.
Answer to Problem 19E
The graph of
Explanation of Solution
Given information :
The functionsis
Use the definition of vertical shifts of graphs,
When graph of
b.
To describe how the graph of the function can be obtained from the graph of
b.
Answer to Problem 19E
The graph of
Explanation of Solution
Given information :
The functionsis
Use the definition of horizontal shifts of graphs,
When graph of
c.
To describe how the graph of the function can be obtained from the graph of
c.
Answer to Problem 19E
The graph of
Explanation of Solution
Given information :
The functionsis
Use the definition of reflecting of graphs,
When graph of
d.
To describe how the graph of the function can be obtained from the graph of
d.
Answer to Problem 19E
The graph of
Explanation of Solution
Given information :
The functionsis
Use the definition of vertical and horizontal shifts of graphs,
When graph of
Chapter 2 Solutions
EBK PRECALCULUS: MATHEMATICS FOR CALCUL
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- • • Let > be a potential for the vector field F = (−2 y³, −6 xy² − 4 z³, −12 yz² + 4 2). Then the value of sin((-1.63, 2.06, 0.57) – (0,0,0)) is - 0.336 -0.931 -0.587 0.440 0.902 0.607 -0.609 0.146arrow_forwardThe value of cos(4M) where M is the magnitude of the vector field with potential ƒ = e² sin(лy) cos(π²) at x = 1, y = 1/4, z = 1/3 is 0.602 -0.323 0.712 -0.816 0.781 0.102 0.075 0.013arrow_forwardThere is exactly number a and one number b such that the vector field F = conservative. For those values of a and b, the value of cos(a) + sin(b) is (3ay + z, 3ayz + 3x, −by² + x) is -0.961 -0.772 -1.645 0.057 -0.961 1.764 -0.457 0.201arrow_forward
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