
a.
To explain what a one to one function is.
a.

Answer to Problem 12RCC
A function with domain A is called a one-to-one function if no two elements of A have the same image, that is,
Explanation of Solution
Given:
The expression one to one function is given.
Concept Used:
The concept of one to one functions is used.
A function with domain A is called a one-to-one function if no two elements of A have the same image, that is,
b.
To explain how we can tell from graph of a function whether it is one to one.
b.

Answer to Problem 12RCC
If the graph of a function f is known, it is easy to determine if the function is one to one. Use the Horizontal Line Test. If no horizontal line intersects the graph of the function f in more than one point, then the function is one to one.
Explanation of Solution
Given:
The expression one to one function is given.
Concept Used:
The concept of one to one functions is used.
If the graph of a function f is known, it is easy to determine if the function is one to one. Use the Horizontal Line Test. If no horizontal line intersects the graph of the function f in more than one point, then the function is one to one.
c.
To define
c.

Answer to Problem 12RCC
The inverse function
Explanation of Solution
Given:
The expression of inverse function
Concept Used:
The concept of inverse functions is used.
The inverse function
The Domain of
d.
To explain how to find the formula of
d.

Answer to Problem 12RCC
The steps to find out the formula of
1. Write
2. Solve this equation for x in terms of y (if possible).
3. Interchange x and y. The resulting equation is
Explanation of Solution
Given:
The expression of inverse function
Concept Used:
The concept of inverse functions is used.
1. Write
2. Solve this equation for x in terms of y (if possible).
3. Interchange x and y. The resulting equation is
e.
To explain how to plot the graph of
e.

Answer to Problem 12RCC
The graph of
Explanation of Solution
Given:
The graph of function f is given.
Concept Used:
The concept of inverse functions is used.
The graph of
Chapter 2 Solutions
EBK PRECALCULUS: MATHEMATICS FOR CALCUL
- Question 3 (6 points) u, v and w are three coplanar vectors: ⚫ w has a magnitude of 10 and points along the positive x-axis ⚫ v has a magnitude of 3 and makes an angle of 58 degrees to the positive x- axis ⚫ u has a magnitude of 5 and makes an angle of 119 degrees to the positive x- axis ⚫ vector v is located in between u and w a) Draw a diagram of the three vectors placed tail-to-tail at the origin of an x-y plane. b) If possible, find w × (u + v) Support your answer mathematically or a with a written explanation. c) If possible, find v. (ū⋅ w) Support your answer mathematically or a with a written explanation. d) If possible, find u (v × w) Support your answer mathematically or a with a written explanation. Note: in this question you can work with the vectors in geometric form or convert them to algebraic vectors.arrow_forwardK Find all values x = a where the function is discontinuous. For each value of x, give the limit of the function as x approaches a. Be sure to note when the limit doesn't exist. x-7 p(x) = X-7 Select the correct choice below and, if necessary, fill in the answer box(es) within your choice. (Use a comma to separate answers as needed.) OA. f is discontinuous at the single value x = OB. f is discontinuous at the single value x= OC. f is discontinuous at the two values x = OD. f is discontinuous at the two values x = The limit is The limit does not exist and is not co or - ∞. The limit for the smaller value is The limit for the larger value is The limit for the smaller value is The limit for the larger value does not exist and is not c∞ or -arrow_forwardK x3 +216 complete the table and use the results to find lim k(x). If k(x) = X+6 X-6 X -6.1 -6.01 - 6.001 - 5.999 - 5.99 -5.9 k(x) Complete the table. X -6.1 -6.01 - 6.001 - 5.999 - 5.99 - 5.9 k(x) (Round to three decimal places as needed.) Find the limit. Select the correct choice below and, if necessary, fill in the answer box within your choice.arrow_forward
- For each of the following series, determine whether the absolute convergence series test determines absolute convergence or fails. For the ¿th series, if the test is inconclusive then let Mi = 4, while if the test determines absolute convergence let Mi 1 : 2: ∞ Σ(−1)"+¹ sin(2n); n=1 Σ n=1 Σ ((−1)”. COS n² 3+2n4 3: (+ 4: 5 : n=1 ∞ n 2+5n3 ПП n² 2 5+2n3 пп n² Σ(+)+ n=1 ∞ n=1 COS 4 2 3+8n3 П ηπ n- (−1)+1 sin (+727) 5 + 2m³ 4 = 8. Then the value of cos(M₁) + cos(2M2) + cos(3M3) + sin(2M) + sin(M5) is -0.027 -0.621 -1.794 -1.132 -1.498 -4.355 -2.000 2.716arrow_forwardi need help with this question i tried by myself and so i am uploadding the question to be quided with step by step solution and please do not use chat gpt i am trying to learn thank you.arrow_forwardi need help with this question i tried by myself and so i am uploadding the question to be quided with step by step solution and please do not use chat gpt i am trying to learn thank you.arrow_forward
- 1. 3 2 fx=14x²-15x²-9x- 2arrow_forwardNo it is not a graded assignment, its a review question but i only have the final answer not the working or explanationarrow_forwardClass, the class silues, and the class notes, whether the series does alternate and the absolute values of the terms decrease), and if the test does apply, determine whether the series converges or diverges. For the ith series, if the test does not apply the let Mi = 2, while if the test determines divergence then M¿ = 4, and if it determines convergence then M¿ = 8. 1: 2: 3 : 4: 5 : ∞ n=1 ∞ (−1)n+1. Σ(-1) +1 n=1 ∞ п 3m² +2 Σ(-1)+1 sin(2n). n=1 ∞ 2n² + 2n +3 4n2 +6 1 e-n + n² 3n23n+1 9n² +3 In(n + 1) 2n+1 Σ(-1) +1 n=1 ∞ Σ(-1)". n=1 Then the value of cos(M₁) + cos(2M2) + cos(3M3) + sin(2M4) + sin(M5) is 1.715 0.902 0.930 -1.647 -0.057 ● 2.013 1.141 4.274arrow_forward
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