Concept explainers
a.
To find the average speed of each winner.
a.
Answer to Problem 31E
The average speed of each of the winner is
Explanation of Solution
Given information:
The graph provided in the question shows the distance as a function of time for each of the three winners.
Calculation:
Since, each of the winner reached finished the race at the same time that is at
So, the average speed of each of the winner must be same.
Therefore,
At
At
Average speed of each of the winner is obtained as:
Hence,
The average speed of each of the winner is
b.
To explain the difference between the ways in which the three runners ran the race.
b.
Answer to Problem 31E
The differencebetween the ways in which the three runners ran the race is that the runner A ran the first half of the race with a higher speed that is
Explanation of Solution
Given information:
The graph provided in the question shows the distance as a function of time for each of the three winners.
The graph showing the distance travelled by the runner at different time interval.
Since, each of the winner reached finished the race at the same time that is at
So, the average speed of each the winner must be same
Therefore
At, t-0 sec, m.
At sec, distance traveled-100 m.
Average speed of each of the winner is obtained as
Hence,
The average speed of each of the winner is 10m/sec.
From the above graph, it can be observed that, distance travelled by A at
Time elapsed
Average speed of runner A from 0 to 5 second is obtained as:
Average speed of runner B from 0 to 5 second is obtained as:
Average speed of runner C from 0 to 5 second is obtained as:
Similarly,
Average speed of runner A from 5 to 10 second is obtained as:
Average speed of runner B from 5 to 10 second is obtained as:
Average speed of runner C from 5 to 10 second is obtained as:
Hence,
It can be concluded easily that the differencebetween the ways in which the three runners ran the race is that the runner A ran the first half of the race with a higher speed that is
Chapter 2 Solutions
EBK PRECALCULUS: MATHEMATICS FOR CALCUL
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