Organic Chemistry, Binder Ready Version
Organic Chemistry, Binder Ready Version
2nd Edition
ISBN: 9781118454312
Author: David R. Klein
Publisher: WILEY
Question
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Chapter 24.7, Problem 39PTS

(a)

Interpretation Introduction

Interpretation:

The each given disaccharides are to be identified whether it is reducing sugar or not.

Concept introduction:

For the carbohydrates,

  • Anomeric position is carried by an OH group for Hemiacetals.
  • Anomeric position is carried by an alkoxy group for acetals.
  • Hemiacetal sugars are in equilibrium with their open chain form.
  • Acetal sugars are not in equilibrium with their open chain form.
  • Reducing sugar: Sugars that contain aldehyde or a free ketone groups that are oxidized to carboxylic acids are classified as reducing sugars. So, the open chain form of sugars can reduce certain oxidizing agents (Tollens’, Fehling’s and Benedict’s) and become carboxylic acids.

To identify: the given compound (a) is a reducing sugar or not.

(b)

Interpretation Introduction

Interpretation:

The each given disaccharides are to be identified whether it is reducing sugar or not.

Concept introduction:

For the carbohydrates,

  • Anomeric position is carried by an OH group for Hemiacetals.
  • Anomeric position is carried by an alkoxy group for acetals.
  • Hemiacetal sugars are in equilibrium with their open chain form.
  • Acetal sugars are not in equilibrium with their open chain form.
  • Reducing sugar: Sugars that contain aldehyde or a free ketone groups that are oxidized to carboxylic acids are classified as reducing sugars. So, the open chain form of sugars can reduce certain oxidizing agents (Tollens’, Fehling’s and Benedict’s) and become carboxylic acids.

(c)

Interpretation Introduction

Interpretation:

The each given disaccharides are to be identified whether it is reducing sugar or not.

Concept introduction:

For the carbohydrates,

  • Anomeric position is carried by an OH group for Hemiacetals.
  • Anomeric position is carried by an alkoxy group for acetals.
  • Hemiacetal sugars are in equilibrium with their open chain form.
  • Acetal sugars are not in equilibrium with their open chain form.
  • Reducing sugar: Sugars that contain aldehyde or a free ketone groups that are oxidized to carboxylic acids are classified as reducing sugars. So, the open chain form of sugars can reduce certain oxidizing agents (Tollens’, Fehling’s and Benedict’s) and become carboxylic acids.

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Chapter 24 Solutions

Organic Chemistry, Binder Ready Version

Ch. 24.5 - Prob. 10ATSCh. 24.5 - Prob. 11ATSCh. 24.5 - Prob. 2LTSCh. 24.5 - Prob. 12LTSCh. 24.5 - Prob. 13ATSCh. 24.5 - Prob. 14ATSCh. 24.5 - Prob. 15ATSCh. 24.5 - Prob. 3LTSCh. 24.5 - Prob. 16PTSCh. 24.5 - Prob. 17ATSCh. 24.5 - Prob. 18ATSCh. 24.5 - Prob. 19CCCh. 24.5 - Prob. 20CCCh. 24.5 - Prob. 21CCCh. 24.5 - Prob. 22CCCh. 24.6 - Prob. 23CCCh. 24.6 - Prob. 24CCCh. 24.6 - Prob. 25CCCh. 24.6 - Prob. 26CCCh. 24.6 - Prob. 27CCCh. 24.6 - Prob. 28CCCh. 24.6 - Prob. 29CCCh. 24.6 - Prob. 30CCCh. 24.6 - Prob. 4LTSCh. 24.6 - Prob. 31PTSCh. 24.6 - Prob. 32ATSCh. 24.6 - Prob. 33ATSCh. 24.6 - Prob. 34CCCh. 24.6 - Prob. 35CCCh. 24.6 - Prob. 36CCCh. 24.6 - Prob. 37CCCh. 24.6 - Prob. 38CCCh. 24.7 - Prob. 5LTSCh. 24.7 - Prob. 39PTSCh. 24.7 - Prob. 40ATSCh. 24.7 - Prob. 41CCCh. 24 - Prob. 42PPCh. 24 - Prob. 43PPCh. 24 - Prob. 44PPCh. 24 - Prob. 45PPCh. 24 - Prob. 46PPCh. 24 - Prob. 47PPCh. 24 - Prob. 48PPCh. 24 - Prob. 49PPCh. 24 - Prob. 50PPCh. 24 - Prob. 51PPCh. 24 - Prob. 52PPCh. 24 - Prob. 53PPCh. 24 - Prob. 54PPCh. 24 - Prob. 55PPCh. 24 - Prob. 56PPCh. 24 - Prob. 57PPCh. 24 - Prob. 58PPCh. 24 - Prob. 59PPCh. 24 - Prob. 60PPCh. 24 - Prob. 61PPCh. 24 - Prob. 62PPCh. 24 - Prob. 63PPCh. 24 - Prob. 64PPCh. 24 - Prob. 65PPCh. 24 - Prob. 66PPCh. 24 - Prob. 67PPCh. 24 - Prob. 68PPCh. 24 - Prob. 69PPCh. 24 - Prob. 70PPCh. 24 - Prob. 71PPCh. 24 - Prob. 72PPCh. 24 - Prob. 73PPCh. 24 - Prob. 74PPCh. 24 - Prob. 75PPCh. 24 - Prob. 76PPCh. 24 - Prob. 77PPCh. 24 - Prob. 78PPCh. 24 - Prob. 79PPCh. 24 - Prob. 80PPCh. 24 - Prob. 81IPCh. 24 - Prob. 82IPCh. 24 - Prob. 83IPCh. 24 - Prob. 84IP
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