Organic Chemistry, Binder Ready Version
Organic Chemistry, Binder Ready Version
2nd Edition
ISBN: 9781118454312
Author: David R. Klein
Publisher: WILEY
Question
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Chapter 24, Problem 43PP

(a)

Interpretation Introduction

Interpretation:

The given Glyceraldehyde is D or L should be identified.

Concept introduction:

Aldose: A monosaccharide in which carbon serves as a backbone and contains an aldehyde group at the beginning.

Ketose: A ketose is a simple sugar unit (monosaccharide) containing one ketone group per molecule.

D and L enantiomers: L isomers have the hydroxyl group attached to the left side of the asymmetric carbon furthest from the carbonyl.

R isomers have the hydroxyl group attached to the right side of the asymmetric carbon furthest from the carbonyl.

D-Glyceraldehyde has the R configuration, while L-glyceraldehyde has the S configuration.

(b)

Interpretation Introduction

Interpretation:

The given Glyceraldehyde is D or L should be identified.

Concept introduction:

Aldose: A monosaccharide in which carbon serves as a backbone and contains an aldehyde group at the beginning.

Ketose: A ketose is a simple sugar unit (monosaccharide) containing one ketone group per molecule.

D and L enantiomers: L isomers have the hydroxyl group attached to the left side of the asymmetric carbon furthest from the carbonyl.

R isomers have the hydroxyl group attached to the right side of the asymmetric carbon furthest from the carbonyl.

D-Glyceraldehyde has the R configuration, while L-glyceraldehyde has the S configuration.

(c)

Interpretation Introduction

Interpretation:

The given Glyceraldehyde is D or L should be identified.

Concept introduction:

Aldose: A monosaccharide in which carbon serves as a backbone and contains an aldehyde group at the beginning.

Ketose: A ketose is a simple sugar unit (monosaccharide) containing one ketone group per molecule.

D and L enantiomers: L isomers have the hydroxyl group attached to the left side of the asymmetric carbon furthest from the carbonyl.

R isomers have the hydroxyl group attached to the right side of the asymmetric carbon furthest from the carbonyl.

D-Glyceraldehyde has the R configuration, while L-glyceraldehyde has the S configuration.

(d)

Interpretation Introduction

Interpretation:

The given Glyceraldehyde is D or L should be identified.

Concept introduction:

Aldose: A monosaccharide in which carbon serves as a backbone and contains an aldehyde group at the beginning.

Ketose: A ketose is a simple sugar unit (monosaccharide) containing one ketone group per molecule.

D and L enantiomers: L isomers have the hydroxyl group attached to the left side of the asymmetric carbon furthest from the carbonyl.

R isomers have the hydroxyl group attached to the right side of the asymmetric carbon furthest from the carbonyl.

D-Glyceraldehyde has the R configuration, while L-glyceraldehyde has the S configuration.

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Instructions: Complete the questions in the space provided. Show all your work 1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l) Initial rate Trial [BrO3] [H*] [Br] (mol/L) (mol/L) | (mol/L) (mol/L.s) 1 0.10 0.10 0.10 8.0 2 0.20 0.10 0.10 16 3 0.10 0.20 0.10 16 4 0.10 0.10 0.20 32 a. Based on the above data what is the rate law expression? b. Solve for the value of k (make sure to include proper units) 2. The proposed reaction mechanism is as follows: i. ii. BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq) HBrO³ (aq) + H* (aq) → H₂BrO3* (aq) iii. H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l) [Fast] [Medium] [Slow] iv. Br₂O₂ (aq) + 4H*(aq) + 4Br‍(aq) → 3Br₂ (l) + H2O (l) [Fast] Evaluate the validity of this proposed reaction. Justify your answer.
е. Д CH3 D*, D20
C. NaOMe, Br Br

Chapter 24 Solutions

Organic Chemistry, Binder Ready Version

Ch. 24.5 - Prob. 10ATSCh. 24.5 - Prob. 11ATSCh. 24.5 - Prob. 2LTSCh. 24.5 - Prob. 12LTSCh. 24.5 - Prob. 13ATSCh. 24.5 - Prob. 14ATSCh. 24.5 - Prob. 15ATSCh. 24.5 - Prob. 3LTSCh. 24.5 - Prob. 16PTSCh. 24.5 - Prob. 17ATSCh. 24.5 - Prob. 18ATSCh. 24.5 - Prob. 19CCCh. 24.5 - Prob. 20CCCh. 24.5 - Prob. 21CCCh. 24.5 - Prob. 22CCCh. 24.6 - Prob. 23CCCh. 24.6 - Prob. 24CCCh. 24.6 - Prob. 25CCCh. 24.6 - Prob. 26CCCh. 24.6 - Prob. 27CCCh. 24.6 - Prob. 28CCCh. 24.6 - Prob. 29CCCh. 24.6 - Prob. 30CCCh. 24.6 - Prob. 4LTSCh. 24.6 - Prob. 31PTSCh. 24.6 - Prob. 32ATSCh. 24.6 - Prob. 33ATSCh. 24.6 - Prob. 34CCCh. 24.6 - Prob. 35CCCh. 24.6 - Prob. 36CCCh. 24.6 - Prob. 37CCCh. 24.6 - Prob. 38CCCh. 24.7 - Prob. 5LTSCh. 24.7 - Prob. 39PTSCh. 24.7 - Prob. 40ATSCh. 24.7 - Prob. 41CCCh. 24 - Prob. 42PPCh. 24 - Prob. 43PPCh. 24 - Prob. 44PPCh. 24 - Prob. 45PPCh. 24 - Prob. 46PPCh. 24 - Prob. 47PPCh. 24 - Prob. 48PPCh. 24 - Prob. 49PPCh. 24 - Prob. 50PPCh. 24 - Prob. 51PPCh. 24 - Prob. 52PPCh. 24 - Prob. 53PPCh. 24 - Prob. 54PPCh. 24 - Prob. 55PPCh. 24 - Prob. 56PPCh. 24 - Prob. 57PPCh. 24 - Prob. 58PPCh. 24 - Prob. 59PPCh. 24 - Prob. 60PPCh. 24 - Prob. 61PPCh. 24 - Prob. 62PPCh. 24 - Prob. 63PPCh. 24 - Prob. 64PPCh. 24 - Prob. 65PPCh. 24 - Prob. 66PPCh. 24 - Prob. 67PPCh. 24 - Prob. 68PPCh. 24 - Prob. 69PPCh. 24 - Prob. 70PPCh. 24 - Prob. 71PPCh. 24 - Prob. 72PPCh. 24 - Prob. 73PPCh. 24 - Prob. 74PPCh. 24 - Prob. 75PPCh. 24 - Prob. 76PPCh. 24 - Prob. 77PPCh. 24 - Prob. 78PPCh. 24 - Prob. 79PPCh. 24 - Prob. 80PPCh. 24 - Prob. 81IPCh. 24 - Prob. 82IPCh. 24 - Prob. 83IPCh. 24 - Prob. 84IP
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