
Interpretation:
D-Sugar of 2-ketohexosesstructures should be drawn.
Concept introduction:
Ketohexoses: A six-carbon monosaccharidewhich is a
The orientation of the carbon atoms in a molecule is arranged vertically from top to bottom.
The C1 carbon is at the top of the orientation, the hydrogen and hydroxyl groups are placed in right and left side of the orientation. D and L form are depends on the arrangement of the hydroxyl group. If the hydroxyl group is in the right side of the molecule in the penultimate (next-to-last) carbon is called as D sugar, if the If the hydroxyl group is in the left side of the molecule in the penultimate (next-to-last) carbon is called as L sugar.
To find: structures of D-sugar of 2-ketohexoses

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Chapter 24 Solutions
Organic Chemistry, Binder Ready Version
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- Complete the mechanismarrow_forwardComplete the mechanismarrow_forward8 00 6 = 10 10 Decide whether each of the molecules in the table below is stable, in the exact form in which it is drawn, at pH = 11. If you decide at least one molecule is not stable, then redraw one of the unstable molecules in its stable form below the table. (If more than unstable, you can pick any of them to redraw.) Check OH stable HO stable Ounstable unstable O OH stable unstable OH 80 F6 F5 stable Ounstable X Save For Later Sub 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy C ཀྭ་ A F7 매 F8 F9 4 F10arrow_forward
- Just try completing it and it should be straightforward according to the professor and TAs.arrow_forwardThe grading is not on correctness, so if you can just get to the correct answers without perfectionism that would be great. They care about the steps and reasoning and that you did something. I asked for an extension, but was denied the extension.arrow_forwardShow your work and do something that is reasonable. It does not have to be 100% correct. Just show something that looks good or pretty good as acceptable answers. Something that looks reasonable or correct would be sufficient. If you can get many of them correct that would be great!arrow_forward
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