Concept explainers
Interpretation: To identify the site where the enzyme that converts disaccharides to monosaccharides is present.
Concept introduction: Carbohydrates are the
Monosaccharides are the simplest carbohydrate units that cannot be hydrolyzed further to give the smallest units. Disaccharides contain two monosaccharide units and on hydrolysis, it gives two monosaccharide units.
In the digestion process, the food molecules break down into small chemical units through hydrolysis. These small chemical units are used by cells present in the body for their
Enzymes are specialized proteins that act as biological catalysts. Enzymes accelerate the biochemical reactions to produce the substances that are needed for cells for their proper functioning.
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EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
- Which of the unknowns is a monosaccharide? Which of the unknowns is a polysaccharide? Explain your reasoning:arrow_forwardPlease correct answer and don't use hend raitingarrow_forward31. Which of the following contain ONLY alpha 1 → 4 linkages between monosaccharides? a. glycogen Ob. starch C. cellulose d. no correct responsearrow_forward
- 6) The disaccharide shown is a но но. HO OH но H. OH B) non reducing sugar A) reducing sugar 7) The glycosidic bond in the following structure can be described as a: OH но. но он OHI B) B (1.1) C) a (14) D) B (14) E) a (2,1) A) a (1,1)arrow_forwardDraw the structure of the disaccharide with a systematic name of: (16)-B-D glucopyranosyl-B-D glucopyranosearrow_forwardQuestion 28 CHOH CHOH A CHOH CHOH 1 CH2 CHOH OH OH OH CH 3 CHOH OH OH он CH он он B 2 OH CH Which lettered subunit is the reducing end? O A В There is more than one reducing end on this sugar structurearrow_forward
- CYCLIZATION OF MONOSACCHARIDESChange the following to Haworth Formula:1. D-idose at C4 ( alpha anomer )2. L- galactose at C5 ( beta anomer )3. D-altrose at C4 ( alpha anomer )4. L-mannose at C5 ( beta anomer )5. D-tallose at C4 ( alpha anomer )arrow_forwardThe glycosidic bond in the following structure can be described as a: но- HO. но OH но H H. H. ÓH A ) α ( 1 1) B) B (1,1) C) a (1,4) D) B (1,4) E) a (2,1) F) B (2,1)arrow_forwardment Score: 24.9% O Resources O Hint Check Ans on 22 of 24 > Disaccharides are joined by glycosidic bonds formed between the anomeric carbon on one monosaccharide and a hydroxy (-OH) group of another monosaccharide. Identify the types of linkages in each of the three disaccharides. Only place three of the linkages. CH,OH OH CH,OH CH,OH OH HO- H OH OH CH,OH нн OH OH OH он OH H HO OH OH он OH OH но OH Answer Bank al al pl - 2 BI -4 al -4 acerarrow_forward
- Question 8 Which of the following is the correct systematic name of the disaccharide shown? OH OH но но HO OH OH OH O a-D-gulopyranosyl-(1-4)-B-D-galactopyranose O a-D-gulopyranosyl-(1–4)-B-D-glucopyranose a-D-glucopyranosyl-(1–3)-B-D-galactopyranose O a-D-glucopyranosyl-(1-3)-B-D-glucopyranosearrow_forwardQ4arrow_forwardAnswers A-D A Monosaccharides exist mainly as ring structures (Haworth projection), in which the aldehyde or ketone group has reacted with a molecule. Carbonyl group (C=O) B Hydroxyl group (OH) D C Amino group (NH2) Carboxylic group (COOH) in the same O O O Oarrow_forward
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