
Concept explainers
(a)
Interpretation: To determine the number of
Concept introduction: Glucose is converted to pyruvate by glycolysis
The Cori cycle is named after its discoverers, Gerty Radnitz Cori, and Carl Cori.
(b)
Interpretation: To determine the number of
Concept introduction: Gluconeogenesis is an eleven-step pathway in which glucose is produced from non-carbohydrate substances. An overview of gluconeogenesis is as follows:
The molecule that contains three carbon atoms is termed as a
(c)
Interpretation: To determine the number of
Concept introduction: In the glycolysis metabolic pathway, a glucose molecule breaks down into two pyruvate molecules. Two ATP molecules and NADH reduced coenzymes are produced in the glycolysis pathway.
The molecule that contains three carbon atoms is termed as a
(d)
Interpretation: To determine the number of
Concept introduction: Lactate dehydrogenase enzymes convert pyruvate to lactate under anaerobic conditions in the human body. This anaerobic reduction of pyruvate to form lactate by enzymes is called lactate fermentation. The overall reaction equation for the conversion of pyruvate to lactate is as follows:
The molecule that contains three carbon atoms is termed as a

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Chapter 24 Solutions
EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
- A mixture of C7H12O2, C9H9OCl, biphenyl and acetone was put together in a gas chromatography tube. Please decide from the GC resutls which correspond to the peak for C7,C9 and biphenyl and explain the reasoning based on GC results. Eliminate unnecessary peaks from Gas Chromatography results.arrow_forwardIs the molecule chiral, meso, or achiral? CI .CH3 H₂C CIarrow_forwardPLEASE HELP ! URGENT!arrow_forward
- Identify priority of the substituents: CH3arrow_forwardHow many chiral carbons are in the molecule? OH F CI Brarrow_forwardA mixture of three compounds Phen-A, Acet-B and Rin-C was analyzed using TLC with 1:9 ethanol: hexane as the mobile phase. The TLC plate showed three spots of R, 0.1 and 0.2 and 0.3. Which of the three compounds (Phen-A; Acet-B or Rin-C) would have the highest (Blank 1), middle (Blank 2) and lowest (Blank 3) spot respectively? 0 CH: 0 CH, 0 H.C OH H.CN OH Acet-B Rin-C phen-A A A <arrow_forward
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