General, Organic, & Biological Chemistry
General, Organic, & Biological Chemistry
3rd Edition
ISBN: 9780073511245
Author: Janice Gorzynski Smith Dr.
Publisher: McGraw-Hill Education
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Chapter 24, Problem 24.37P
Interpretation Introduction

(a)

Interpretation:

The step of glycolysis in which ATP are formed should be determined.

Concept Introduction:

Aerobic respiration occurs in two steps:

  • Glycolysis
  • Citric acid cycle

Glycolysis is the first step that forms pyruvate as given below:

Glucose +   2NAD+ + 4ADP + 2Pi  2 Pyruvate + 4ATP + 2NADH + 2H+

In the presence of oxygen means aerobic respiration, this pyruvate enters the Krebs cycle and extracts energy in the form of electrons transfer. Electrons are transferred from the pyruvate to the receptors like NAD+, GDP, and FAD and CO2 gas is formed as the waste product. The products of citric acid cycles act as precursors for electron transport chains.

Expert Solution
Check Mark

Answer to Problem 24.37P

In glycolysis, ATP's are formed in step-7 and 10.

Explanation of Solution

The metabolism of glucose starts from the glycolysis process. It is the first step in cellular metabolism to extract energy from glucose. It is the sequence of 10 enzyme-catalyzed reactions that involve the conversion of glucose molecules into pyruvate with the production of ATP molecules.

The overall reaction of glycolysis must be written as:

  C6H12O6 + 2 NAD+ + 2 ADP + 2 P  2  (CH3(C=O)COOH + 2 ATP + 2 NADH + 2 H+

Two steps; 7th and 10th step are involved in the production of ATP;

  • Conversion of 1,3-bisphosphoglycerate to 3-phosphoglycerate occurs with the conversion of ADP to form ATP in the presence of Phosphoglycerate kinase that transfers a phosphate group.
  • Conversion of phosphoenolpyruvate (PEP) to pyruvic acid with the conversion of ATP in the presence enzyme pyruvate kinase
Interpretation Introduction

(b)

Interpretation:

The step of glycolysis which uses ATP molecules should be determined.

Concept Introduction:

Aerobic respiration occurs in two steps:

  • Glycolysis
  • Citric acid cycle

Glycolysis is the first step that forms pyruvate as given below:

  Glucose +   2NAD+ + 4ADP + 2Pi  2 Pyruvate + 4ATP + 2NADH + 2H+

In the presence of oxygen means aerobic respiration, this pyruvate enters the Krebs cycle and extracts energy in the form of electrons transfer. Electrons are transferred from the pyruvate to the receptors like NAD+, GDP, and FAD and CO2 gas is formed as the waste product. The products of citric acid cycles act as precursors for electron transport chains.

Expert Solution
Check Mark

Answer to Problem 24.37P

In glycolysis, ATP's are formed in step-1 and 3.

Explanation of Solution

The metabolism of glucose starts from the glycolysis process. It is the first step in cellular metabolism to extract energy from glucose. It is the sequence of 10 enzyme-catalyzed reactions that involves the conversion of glucose molecules into pyruvate with the production of ATP molecules.

The overall reaction of glycolysis must be written as:

  C6H12O6 + 2 NAD+ + 2 ADP + 2 P  2  (CH3(C=O)COOH + 2 ATP + 2 NADH + 2 H+

Two steps; 1st and 3rdstep use ATP molecules.

  • The first step in glycolysis, glucose converts to glucose-6-phosphate in the presence of hexokinase. It uses energy in the form of ATP and converts it to ADP molecule.

General, Organic, & Biological Chemistry, Chapter 24, Problem 24.37P , additional homework tip  1

  • Phosphofructokinase, with magnesium as a cofactor, changes fructose 6-phosphate into fructose 1, 6-bisphosphate.

General, Organic, & Biological Chemistry, Chapter 24, Problem 24.37P , additional homework tip  2

Interpretation Introduction

(c)

Interpretation:

The step of glycolysis which forms a reduce coenzyme should be determined.

Concept Introduction:

Aerobic respiration occurs in two steps:

  • Glycolysis
  • Citric acid cycle

Glycolysis is the first step that forms pyruvate as given below:

  Glucose +   2NAD+ + 4ADP + 2Pi  2 Pyruvate + 4ATP + 2NADH + 2H+

In the presence of oxygen means aerobic respiration, this pyruvate enters the Krebs cycle and extracts energy in the form of electrons transfer. Electrons are transferred from the pyruvate to the receptors like NAD+, GDP, and FAD and CO2 gas is formed as the waste product. The products of citric acid cycles act as precursors for electron transport chains.

Expert Solution
Check Mark

Answer to Problem 24.37P

In glycolysis, step-6 forms a reduced coenzyme NADH.

Explanation of Solution

The metabolism of glucose starts from the glycolysis process. It is the first step in cellular metabolism to extract energy from glucose. It is the sequence of 10 enzyme-catalyzed reactions which involves the conversion of glucose molecules into pyruvate with the production of ATP molecules.

The overall reaction of glycolysis must be written as:

  C6H12O6 + 2 NAD+ + 2 ADP + 2 P  2  (CH3(C=O)COOH + 2 ATP + 2 NADH + 2 H+

In the 6th step of glycolysis, glyceraldehyde-3-phosphate converts to 1,3-bisphosphoglycerate. It is a dehydrogenation step that occurs in the presence of Glyceraldehyde-3-phosphate dehydrogenase (GAPDH) and converts NAD+ to NADH and H+ ions.

General, Organic, & Biological Chemistry, Chapter 24, Problem 24.37P , additional homework tip  3

Interpretation Introduction

(c)

Interpretation:

The step of glycolysis which breaks a C-C bond should be determined.

Concept Introduction:

Aerobic respiration occurs in two steps:

  • Glycolysis
  • Citric acid cycle
    • Glycolysis is the first step that forms pyruvate as given below:

      Glucose + 2ATP + 2NAD+ + 4ADP + 2Pi  2 Pyruvate + 4ATP + 2NADH + 2H+

    In the presence of oxygen means aerobic respiration, this pyruvate enters the Krebs cycle and extracts energy in the form of electrons transfer. Electrons are transferred from the pyruvate to the receptors like NAD+, GDP, and FAD and CO2 gas is formed as the waste product. The products of citric acid cycles act as precursors for electron transport chains.

Expert Solution
Check Mark

Answer to Problem 24.37P

In glycolysis, step-4breaks a C-C bond.

Explanation of Solution

The metabolism of glucose starts from the glycolysis process. It is the first step in cellular metabolism to extract energy from glucose. It is the sequence of 10 enzyme-catalyzed reactions which involves the conversion of glucose molecules into pyruvate with production of ATP molecules.

The overall reaction of glycolysis must be written as:

  C6H12O6 + 2 NAD+ + 2 ADP + 2 P  2  (CH3(C=O)COOH + 2 ATP + 2 NADH + 2 H+

In the 4thstep of glycolysis, in the presence of enzyme Aldolase, fructose 1, 6-bisphosphate breaks into two sugar molecules. These sugar molecules are isomers of each other; dihydroxyacetone phosphate (DHAP) and glyceraldehyde 3-phosphate (GAP).

General, Organic, & Biological Chemistry, Chapter 24, Problem 24.37P , additional homework tip  4

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Chapter 24 Solutions

General, Organic, & Biological Chemistry

Ch. 24.4 - Prob. 24.11PCh. 24.5 - Prob. 24.12PCh. 24.5 - Prob. 24.13PCh. 24.5 - Prob. 24.14PCh. 24.6 - Prob. 24.15PCh. 24.7 - Prob. 24.16PCh. 24.7 - Prob. 24.17PCh. 24.7 - Prob. 24.18PCh. 24.7 - Prob. 24.19PCh. 24.7 - Use the number of molecules of ATP formed from the...Ch. 24.7 - Prob. 24.21PCh. 24.8 - Prob. 24.22PCh. 24.8 - Prob. 24.23PCh. 24.8 - Prob. 24.24PCh. 24.8 - Prob. 24.25PCh. 24.9 - Prob. 24.26PCh. 24.9 - Prob. 24.27PCh. 24.9 - Prob. 24.28PCh. 24 - Analyze each reaction by considering the...Ch. 24 - Analyze each reaction by considering the...Ch. 24 - Prob. 24.31PCh. 24 - Prob. 24.32PCh. 24 - Prob. 24.33PCh. 24 - Prob. 24.34PCh. 24 - Prob. 24.35PCh. 24 - Prob. 24.36PCh. 24 - Prob. 24.37PCh. 24 - Prob. 24.38PCh. 24 - Glucose is completely metabolized to six molecules...Ch. 24 - Why is glycolysis described as an anaerobic...Ch. 24 - Write the overall equation with key coenzymes for...Ch. 24 - Prob. 24.42PCh. 24 - Prob. 24.43PCh. 24 - Prob. 24.44PCh. 24 - Consider the aerobic and anaerobic avenues of...Ch. 24 - Prob. 24.46PCh. 24 - Prob. 24.47PCh. 24 - Prob. 24.48PCh. 24 - Prob. 24.49PCh. 24 - Prob. 24.50PCh. 24 - Prob. 24.51PCh. 24 - Prob. 24.52PCh. 24 - Prob. 24.53PCh. 24 - Prob. 24.54PCh. 24 - Prob. 24.55PCh. 24 - Prob. 24.56PCh. 24 - Prob. 24.57PCh. 24 - Prob. 24.58PCh. 24 - Prob. 24.59PCh. 24 - Prob. 24.60PCh. 24 - Prob. 24.61PCh. 24 - Prob. 24.62PCh. 24 - Prob. 24.63PCh. 24 - Prob. 24.64PCh. 24 - Prob. 24.65PCh. 24 - Prob. 24.66PCh. 24 - Prob. 24.67PCh. 24 - Fill in the boxes with the number of moles of each...Ch. 24 - Prob. 24.69PCh. 24 - Prob. 24.70PCh. 24 - Prob. 24.71PCh. 24 - Prob. 24.72PCh. 24 - Prob. 24.73PCh. 24 - Prob. 24.74PCh. 24 - Prob. 24.75PCh. 24 - Prob. 24.76PCh. 24 - What is the difference between ketogenic and...Ch. 24 - Prob. 24.78PCh. 24 - Prob. 24.79PCh. 24 - Draw the structure of the keto acid formed by the...Ch. 24 - Draw the products formed in each transamination...Ch. 24 - Prob. 24.82PCh. 24 - Prob. 24.83PCh. 24 - Prob. 24.84PCh. 24 - What metabolic intermediate is formed from the...Ch. 24 - What metabolic intermediate is formed from the...Ch. 24 - Prob. 24.87PCh. 24 - Prob. 24.88PCh. 24 - Prob. 24.89PCh. 24 - What is the cause of the pain and cramping in a...Ch. 24 - Prob. 24.91PCh. 24 - Prob. 24.92PCh. 24 - Prob. 24.93PCh. 24 - Prob. 24.94PCh. 24 - Prob. 24.95PCh. 24 - Prob. 24.96PCh. 24 - What type of enzyme would catalyze the conversion...Ch. 24 - Prob. 24.98PCh. 24 - Prob. 24.99CPCh. 24 - Prob. 24.100CPCh. 24 - Prob. 24.101CPCh. 24 - Prob. 24.102CP
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