Concept explainers
(a)
Interpretation:
The compound
Concept introduction:
NMR spectroscopy is a technique used to determine the unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy. The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region.
(b)
Interpretation:
The compound
Concept introduction:
NMR spectroscopy is a technique used to determine the unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as as a proton in the NMR spectroscopy. The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region.
(c)
Interpretation:
The compound
Concept introduction:
NMR spectroscopy is a technique used to determine the unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is known as a proton in the NMR spectroscopy. The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region.
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Organic Chemistry Study Guide and Solutions
- Is it possible to distinguish between the following compounds using the spectroscopic techniques covered in CHE331? If so, discuss how. If not, discuss why.Benzonitrile vs Benzaldehyde(a) UV spectroscopy(b) IR spectroscopy(c) Mass spectrometry(d) 13C NMR spectroscopy(e) 1H NMR spectroscopyarrow_forwardCompound A has molecular formula C8H8O. Its 1H-NMR spectrum shows a singlet of integral 3 at 2.58 ppm and a multiplet of integral 5 at 7.84 ppm. Its 13C-NMR shows six signals. The IR spectrum of A shows a noteworthy stretch at 1698 cm-1. - Identify Compound A, explaining your reasoning Compound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The 1H-NMR spectrum of B shows three singlets, one at 2.52 pm of integral 3, one at 6.67 ppm of integral 1, and one at 7.94 ppm of integral 2. The 13C-NMR spectrum of B shows six signals. - Identify compound B, explaining your reasoning Compound B is treated with methylmagnesium bromide and then aqueous acid to generate compound C. The 1H-NMR spectrum of C shows four singlets, one at 1.42 ppm of integral 6, one at 2.3 ppm of integral 1, one at 8.52 ppm of integral 2, and one at 8.97 ppm of integral 1. The 13C-NMR spectrum of C shows six signals. The IR spectrum of C shows a noteworthy broad stretch at 3326 cm-1. -…arrow_forward24.82 When the compound shown here is heated, ethene gas is evolved and a product with the formula C14H3O2 is formed. The 'H NMR and 13C NMR spectra of C14H8O2 are shown below. (There are two signals >150 ppm in the 13C NMR spectrum. Recall that the 13C NMR signal at 77 ppm is from the CDCI3 solvent.) (a) Draw the structure of C,14H3O2. (b) Draw the mechanism that accounts for its formation. (c) What is the main driving force that favors the products of this reaction? ? C14H3O2 C14H8O2 9. 8 7 6 4 3 2 1 250 200 150 100 50 Chemical shift (ppm) Chemical shift (ppm)arrow_forward
- Compound A has molecular formula C5H8Br4 but shows only one singlet in the 1H-NMR spectrum. Suggest a structure for A and explain your reasoning.arrow_forwardArrange the members of each group in order of decreasing basicity: (a) Ammonia, aniline, methylamine (b) Acetanilide, aniline, N-methylaniline (c) 2,4-Dichloroaniline, 2,4-dimethylaniline, 2,4-dinitroaniline (d) 3,4-Dichloroaniline, 4-chloro-2-nitroaniline, 4-chloro-3-nitroaniline (e) Dimethylamine, diphenylamine, N-methylanilinearrow_forwardCompound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The 1H-NMR spectrum of B shows two singlets, one at 2.52 pm and one at 8.13 ppm. The 13C-NMR spectrum of B shows five signals. The mass spectrum of B shows a peak at m/z = 260 and another peak at m/z = 262; the relative height of the two peaks is 1:1 respectively. - Identify compound B, explaining your reasoningarrow_forward
- (b) One isomer of dimethoxybenzoic acid has 1H NMR spectrum dµ (ppm) 3.85 (6H, s), 6.63 (1H, t, J 2 Hz), and 7.17 (2H, d, J 2Hz), One isomer of coumalic acid has 'H NMR spectrum dн (ppm) 6.41 (1H, d, J 10 Hz), 7.82 (1H, dd, J 2 Hz, 10 Hz) and 8.51 (1H, d, J 2Hz). In each case, which isomer is represented here? The bonds sticking into the centre of the ring can be to any carbon atom. Note: COOH proton is not indicated in the spectra MeO HO₂C CO2H MeO dimethoxybenzoic acid coumalic acidarrow_forwardA and B are isomeric dicarbonyl compounds of the molecular formula C5H&O2. The 'H NMR spectrum of A contains a singlet at 2.05 ppm and another singlet at 5.40 ppm. The 'H NMR spectrum of B contains three signals: a singlet at 2.3 ppm, a triplet at 1.10 ppm and a quartet at 2.70 ppm. Suggest structures for A and B and draw them in their respective boxes below. 1st attemptarrow_forwardCompounds B and C are isomers with molecular formula C5H9BrO2. The 1H NMR spectrum of compounds B and C are shown below. The IR spectrum corresponding to compound B showed strong absorption bands at 1739, 1225, and 1158 cm-1, while the spectrum corresponding to compound C have strong bands at 1735, 1237, and 1182 cm-1. 1.Based on the information provided, determine the structure of compounds B and C. 2.Assign all peaks in 1H NMR spectrum of compounds B and C.arrow_forward
- The 1H-NMR spectrum of Compound D of molecular formula C10H12O shows three singlets – δ 2.20 (6H, s), 4.86 (4H), 7.10 (2H) ppm. Its 13C-NMR spectrum has five signals – 20, 74, 127, 135, 146 ppm. Suggest a structure for this compound.arrow_forwardAn organic compound B with formula C6H14O has the following: IR Spectroscopy 2974 cm-1, 1080 cm-1 Mass Spectrometry 102 (M+), 87, 73 1H NMR Spectroscopy Eight signals at δ 1.10 (d, 3H), 1.13 (dd, 3H), 1.14 (dd, 3H), 1.59 (ddq, 1H), 1.60 (ddq, 1H), 3.19 (ddq, 1H), 3.51 (dq, 1H), 3.50 (dq, 1H). Compound B is obtained by the reaction of compound A with NaH followed by CH3CH2Br. The stereochemistry of A is "S" Using this information, deduce a plausible structure for Compound A with correct stereochemistry.arrow_forward[24166 Ji 10201900 (c) Propose reagents and conditions for the following 3-step synthesis of secondary amine 10, starting from azide 9. Your answer should include reagents and conditions for all three steps and a full curly arrow mechanism for the benzylation step (i.e. from primary amine 11 to secondary amine 12). Comment on any predicted selectivity. N3 m obydob is 10 br 9, 0-0 25 ilqmoxs of ozonit o = =Et Isaiavda se ni tons 3 steps Benzylation step: bre quotesmotional sies no H₂NY 11:0g 00S - (0=01 BOYH2OJA 0-3168 A3T23 ZI N H ZI H 12 10 wwww -Etarrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning