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(a)
Interpretation:
The product obtained in the reaction of
Concept introduction:
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Answer to Problem 23.45AP
The product
Explanation of Solution
When
Figure 1
The product obtained in the reaction of
(b)
Interpretation:
The product obtained in the reaction of
Concept introduction:
Amines are the organic compounds that are formed by replacement of hydrogen from ammonia with a substituent. It may be alkyl or aryl group. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water. The replacement of hydrogen atom attached to a carbon atom of electron-rich benzene ring by an incoming electrophile is known as electrophilic aromatic substitution reaction.
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Answer to Problem 23.45AP
The product obtained in the reaction of
Explanation of Solution
When
Figure 2
The product obtained in the reaction of
(c)
Interpretation:
The product obtained in the reaction of
Concept introduction:
Amines are the organic compounds that are formed by replacement of hydrogen from ammonia with a substituent. It may be alkyl or aryl group. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.
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Answer to Problem 23.45AP
The product
Explanation of Solution
When
Figure 3
The product obtained in the reaction of
(d)
Interpretation:
The product obtained in the reaction of
Concept introduction:
Amines are the organic compounds that are formed by replacement of hydrogen from ammonia with a substituent. It may be alkyl or aryl group. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.
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Answer to Problem 23.45AP
The product
Explanation of Solution
When
Figure 4
The product obtained in the reaction of
(e)
Interpretation:
The product obtained in the reaction of
Concept introduction:
Amines are the organic compounds that are formed by replacement of hydrogen from ammonia with a substituent. It may be alkyl or aryl group. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.
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Answer to Problem 23.45AP
The product
Explanation of Solution
The reagents,
Figure 5
The product obtained in the reaction of
(f)
Interpretation:
The product obtained in the reaction of
Concept introduction:
Amines are the organic compounds that are formed by replacement of hydrogen from ammonia with a substituent. It may be alkyl or aryl group. Hofmann elimination reaction occurs as an anti-elimination reaction. In this reaction, the starting material is quaternary ammonium hydroxide. When quaternary ammonium hydroxide is heated,
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Answer to Problem 23.45AP
The product
Explanation of Solution
Hofmann elimination reaction occurs as an anti-elimination reaction. In this reaction, the starting material is quaternary ammonium hydroxide. In the given case, when
Figure 6
The product obtained in the reaction of
(g)
Interpretation:
The product obtained in the reaction of
Concept introduction:
Amines are the organic compounds that are formed by replacement of hydrogen from ammonia with a substituent. It may be alkyl or aryl group. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water. Reductive amination reaction is the conversion of the carbonyl group to the amine or it converts one amine to newer amine.
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Answer to Problem 23.45AP
The product,
Explanation of Solution
Reductive amination reaction is the conversion of the carbonyl group to the amine or it converts one amine to new amine. In the given case, when
Figure 7
The product obtained in the reaction of
(h)
Interpretation:
The product obtained in the reaction of
Concept introduction:
Amines are the organic compounds that are formed by replacement of hydrogen from ammonia with a substituent. It may be alkyl or aryl group. Amines are basic in nature because the nitrogen can donate its lone pairs and also the ability of the nitrogen to accept the proton in water.
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Answer to Problem 23.45AP
The product
Explanation of Solution
When
Figure 8
The product obtained in the reaction of
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Chapter 23 Solutions
Organic Chemistry Study Guide and Solutions
- The following 'H NMR spectrum was taken with a 750 MHz spectrometer: 1.0 0.5 0.0 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 ' 2.0 1.0 0.0 (ppm) What is the difference Av in the frequency of RF ac Δν ac radiation absorbed by the a and c protons? (Note: it's not equal to the difference in chemical shifts.) Round your answer to 2 significant digits, and be sure it has an appropriate unit symbol. = O O a will shift left, c will shift right. O a will shift right, c will shift left. a and c will both shift left, with more space between them. Suppose a new spectrum is taken with a 500 MHz spectrometer. What will be true about this new spectrum? O a and c will both shift left, with less space between them. O a and c will both shift right, with more space between them. O a and c will both shift right, with less space between them. Which protons have the largest energy gap between spin up and spin down states? O None of the above. ○ a Ob Explanation Check C Ar B 2025 McGraw Hill LLC. All Rights Reserved.…arrow_forwardWhat mass of Na2CO3 must you add to 125g of water to prepare 0.200 m Na2CO3? Calculate mole fraction of Na2CO3, mass percent, and molarity of the resulting solution. MM (g/mol): Na2CO3 105.99; water 18.02. Final solution density is 1.04 g/mL.arrow_forward(ME EX2) Prblms Can you please explain problems to me in detail, step by step? Thank you so much! If needed color code them for me.arrow_forward
- Experiment #8 Electrical conductivity & Electrolytes. Conductivity of solutions FLINN Scientific Scale RED LED Green LED LED Conductivity 0 OFF OFF 1 Dim OFF 2 medium OFF 3 Bright Dim Low or Nowe Low Medium High 4 Very Bright Medium nd very high AA Δ Δ Δ Δ Δ Δ Δ Δ Δ Δ Δ SE=Strong Electrolyte, FE = Fair Electrolyte CWE = Weak Electrolyte, NE= Noni Electrolyte, #Solutions 1 0.1 M NaCl 2/1x 102 M NaCl, 3/1X103 M Nall Can Prediction M Observed Conductivity Very bright red Bright red Dim red you help me understand how I'm supposed to find the predictions of the following solutions? I know this is an Ionic compound and that the more ions in a solution means it is able to carry a charge, right? AAAA Darrow_forward(SE EX 2) Prblsm 4-7: Can you please explain problems 4-7 and color code if needed for me. (step by step) detail explanationsarrow_forward(SE EX 2) Problems 8-11, can you please explain them to me in detail and color-code anything if necessary?arrow_forward
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