Chapter 22.2, Problem 12R

To determine

Thedifference in pH strength of the two solutions.

Answer to Problem 12R

The solution of pH $2.4$ is $\underset{\_}{100}$ times more acidic than the solution of pH $4.4$ .

Explanation of Solution

Given:

The pH of first solution = $2.4$

The pH of second solution = $4.4$

The difference in pH strength = ${10}^n$ , where n is the difference between pHs.

Calculation:

As per the problem,

The pH of first solution = $2.4$

The pH of second solution = $4.4$

The difference between pH of the two solutions = $n=4.4-2.4=2$

The difference in pH strength = ${10}^n={10}^2=100$ .

The lower the pH value, more acidic the solution.

Therefore, the first solution is hundred times more acidic than the second solution.

Conclusion:The solution of pH $2.4$ is $100$ times more acidic than the solution of pH $4.4$ .