Chapter 22, Problem 16STP

To determine

To know: The name of salts produced from given acid and base reactions.

Explanation of Solution

Introduction:

The reaction of acid and base results in the formation of a salt and water. This is known as neutralization reaction. The general reaction is represented as follows:

  $\text{HA}+\text{BOH}\to \text{AB}+{\text{H}}_{\text{2}}\text{O}$

Here, HA is acid, BOH is base, AB is salt and ${\text{H}}_{\text{2}}\text{O}$ is water.

The above reaction is a neutralization reaction because resultant solution is neutral in nature.

The given acid-base pairs are as follows:

  $\text{HCl}+\text{NaOH, HCl}+\text{Mg}{\left(\text{OH}\right)}_{\text{2}}\text{ and HBr}+\text{ KOH}$

Here, HCl and HBr are strong acids and NaOH, $\text{Mg}{\left(\text{OH}\right)}_{\text{2}}$ and KOH are strong bases.

Strong acids and bases react completely to form respective salts and water.

The reactions will be as follows:

  $\begin{array}{l}\text{HCl}\left(aq\right)+\text{NaOH}\left(aq\right)\to \text{NaCl}\left(s\right)+{\text{H}}_{\text{2}}\text{O}\left(l\right)\\ \text{2HCl}\left(aq\right)+\text{Mg}{\left(\text{OH}\right)}_{\text{2}}\left(aq\right)\to {\text{MgCl}}_2\left(s\right)+2{\text{H}}_{\text{2}}\text{O}\left(l\right)\\ \text{HBr}\left(aq\right)+\text{ KOH}\left(aq\right)\to \text{KBr}\left(s\right)+{\text{H}}_{\text{2}}\text{O}\left(l\right)\end{array}$

Here, the salts produced are NaCl, ${\text{MgCl}}_2$ and KBr and the name of the salts are sodium chloride, magnesium chloride and potassium bromide respectively.

Conclusion:

Thus, the name of the salts is sodium chloride, magnesium chloride and potassium bromide.