Chemistry: Principles and Practice
3rd Edition
ISBN: 9780534420123
Author: Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher: Cengage Learning
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Chapter 22, Problem 77QE
(a)
Interpretation Introduction
Interpretation:
The structural formula for
Concept introduction:
The structural representation of organic compound can be done in
- Expanded structural formula
- Condensed structural formula
- Skeletal structural formula
- Line-angle structural formula
Structural formula which shows all the atoms in a molecule along with all the bonds that is connecting the atoms present in the molecule is known as expanded structural formula.
Structural formulas in which grouping of atoms are done and in which the central atoms along with the other atoms are connected to them are treated as group is known as Condensed structural formula.
Structural formula that shows the bonding between carbon atoms alone in the molecule, ignoring the hydrogen atoms being shown explicitly is known as skeletal structural formula.
Structural formula where a line represent carbon-carbon bond and the carbon atom is considered to be present in each point and the end of lines is known as line-angle structural formula.
(b)
Interpretation Introduction
Interpretation:
The structural formula for
Concept introduction:
Refer to part (a).
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It is not unexpected that the methoxyl substituent on a cyclohexane ring
prefers to adopt the equatorial conformation.
OMe
H
A G₂ = +0.6 kcal/mol
OMe
What is unexpected is that the closely related 2-methoxytetrahydropyran
prefers the axial conformation:
H
H
OMe
OMe
A Gp=-0.6 kcal/mol
Methoxy: CH3O group
Please be specific and clearly write the reason why this is observed. This effect that provides
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example, the staggered conformer of ethane is more stable than eclipsed owing to bonding MO
interacting with anti-bonding MO...]
206 Pb
82
Express your answers as integers. Enter your answers separated by a comma.
▸ View Available Hint(s)
VAΣ
ΜΕ ΑΣΦ
Np, N₁ = 82,126
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Previous Answers
?
protons, neutrons
Please draw the inverted chair forms of the products for the two equilibrium reactions
shown below. Circle the equilibrium reaction that would have a AG = 0, i.e., the relative energy of
the reactant (to the left of the equilibrium arrows) equals the relative energy of the product? [No
requirement to show or do calculations.]
CH3
CH3
HH
CH3
1
-CH3
Chapter 22 Solutions
Chemistry: Principles and Practice
Ch. 22 - Prob. 1QECh. 22 -
Explain what is special about the element carbon...Ch. 22 - Prob. 3QECh. 22 - Prob. 4QECh. 22 - Prob. 5QECh. 22 - Prob. 6QECh. 22 - Prob. 7QECh. 22 - Prob. 8QECh. 22 - Prob. 9QECh. 22 - Prob. 10QE
Ch. 22 - Prob. 11QECh. 22 - Prob. 12QECh. 22 - Prob. 13QECh. 22 - Prob. 14QECh. 22 - Prob. 15QECh. 22 - Prob. 16QECh. 22 - Prob. 17QECh. 22 - Prob. 18QECh. 22 - Prob. 19QECh. 22 - Prob. 20QECh. 22 - Prob. 21QECh. 22 - Prob. 22QECh. 22 - Prob. 23QECh. 22 - Prob. 24QECh. 22 - Prob. 25QECh. 22 - Prob. 26QECh. 22 - Prob. 27QECh. 22 - Prob. 28QECh. 22 - Prob. 29QECh. 22 - Prob. 30QECh. 22 - Prob. 31QECh. 22 - Prob. 32QECh. 22 - Prob. 33QECh. 22 - Prob. 34QECh. 22 - Prob. 35QECh. 22 - Prob. 36QECh. 22 - Prob. 37QECh. 22 - Prob. 38QECh. 22 - Prob. 39QECh. 22 - Prob. 40QECh. 22 - Prob. 41QECh. 22 - Prob. 42QECh. 22 - Prob. 43QECh. 22 - Prob. 44QECh. 22 - Prob. 45QECh. 22 - Prob. 46QECh. 22 - Prob. 47QECh. 22 - Prob. 48QECh. 22 - Prob. 49QECh. 22 - Prob. 50QECh. 22 - Prob. 51QECh. 22 - Prob. 52QECh. 22 - Prob. 53QECh. 22 - Prob. 54QECh. 22 - Name the following compounds. (a) FCH2CH2CH2OH (b)...Ch. 22 - Prob. 56QECh. 22 - Prob. 57QECh. 22 - Prob. 58QECh. 22 - Prob. 59QECh. 22 - Prob. 60QECh. 22 - Prob. 61QECh. 22 - Prob. 62QECh. 22 - Prob. 63QECh. 22 - Prob. 64QECh. 22 - Prob. 65QECh. 22 - Prob. 66QECh. 22 - Prob. 67QECh. 22 - Prob. 68QECh. 22 - Prob. 69QECh. 22 - Prob. 70QECh. 22 - Prob. 71QECh. 22 - Prob. 72QECh. 22 - Prob. 73QECh. 22 - Prob. 74QECh. 22 - Prob. 75QECh. 22 - Prob. 76QECh. 22 - Prob. 77QECh. 22 - Prob. 78QECh. 22 - Prob. 79QECh. 22 - Prob. 80QECh. 22 - Prob. 81QECh. 22 - Prob. 82QECh. 22 - Prob. 83QECh. 22 - Prob. 84QECh. 22 - Prob. 85QECh. 22 - Prob. 86QECh. 22 - Prob. 87QECh. 22 - Prob. 88QE
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- 5. Please consider the Newman projection of tartaric acid drawn below as an eclipsed conformer (1). Please draw the most stable conformer and two intermediate energy conformers noting that staggered conformers are lower in energy than eclipsed forms even if the staggered conformers have gauche relationships between groups. [Draw the substituents H and OH on the front carbons and H, OH and CO₂H on the back carbons based on staggered forms. -CO₂H is larger than -OH.] OH COH ICOOH COOH COOH 1 2 COOH COOH 3 4 Staggered Staggered Staggered (most stable) Indicate the number of each conformer above (1, 2, 3 and 4) that corresponds to the relative energies below. Ref=0 Rotation 6. (60 points) a. Are compounds 1 and 2 below enantiomers, diastereomers or identical? OH OH HO HO LOH HO HO OH 2 OH OH b. Please complete the zig-zag conformation of the compound (3R,4S)-3,4-dichloro-2,5-dimethylhexane by writing the respective atoms in the boxes. 3.arrow_forwardThe plutonium isotope with 144 neutrons Enter the chemical symbol of the isotope.arrow_forwardThe mass ratio of sodium to fluorine in sodium fluoride is 1.21:1. A sample of sodium fluoride produced 26.1 gg of sodium upon decomposition. How much fluorine was formed?arrow_forward
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