Interpretation:
A stepwise procedure with equations to show how to separate a mixture of
Concept Introduction:
Separation of the components of a mixture of organic compounds is based on the difference in their solubility in water and an organic solvent immiscible with water.
Advantage is taken of the difference in solubility of a basic (or acidic) compound and its conjugate base (or acid) in water.
Conjugate base of an acid or conjugate acid of a base are salts. Their ionic nature leads to a higher solubility in water as compared to a non-polar (or weakly polar) organic solvent. They are extracted into the aqueous phase containing an acid or a base from the solution of the mixture in a suitable organic solvent such as diethyl ether.
The base or the acid can then be recovered from the aqueous phase by neutralizing the conjugate acid (or base) with a strong base such as sodium hydroxide (or a strong acid such as hydrochloric acid). The recovered base (or acid) being insoluble separates out.
A neutral compound remains in ether solution (organic phase) from which it can be recovered by allowing ether to evaporate.
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Chapter 22 Solutions
ORGANIC CHEMISTRY-PACKAGE >CUSTOM<
- Use the systematic treatment of equilibrium to determine the pH and the concentrations of all species in a saturated aqueous solution of SrF2. Do not include activity coefficients. The solubility of SrF2 is governed by Ksp for the salt, hydrolysis of F- and of Sr2+, and by ion pairing between Sr2 + and F-. PK(SrF2) = 8.58, PK(HF) = 3.17, pkw = 14.00, pk for the formation of (SrOH+) = 13.18, pk for the formation of (SrF+) = 0.14 Show all your work and upload your answers here. 1 - Write the pertinent reactions. 2 - Write mass balance and charge balance equations. 3 - Write the equilibrium constant expressions. 4 - Count the equations and unknowns. 5- If the problem is solvable make suitable approximations and find the concentrations and the pH.arrow_forwardPlease correct answer and don't use hand ratingarrow_forwardHow might you prepare each of the following using a nucleophilic substitution reaction at some step? (a) (b) (c) (d) CH3 CH3C CCHCH3 CH3 CH3 0 CCH3 ☐ CH3 CH3CH2CH2CH2CN CH3CH2CH2NH2arrow_forward
- No AI response. Please reference attachment for assistance with chemistry. Will upvote if satisfied. Thanks againarrow_forwardManganese(II) Arsenate is insoluble in water at room temperature. (Note: Arsenate = AsO4³-) In the presence of aqueous ammonia, solid Manganese(II) Arsenate becomes more soluble and aqueous tetraamminemanganese (II) ion forms. When solid Manganese(II) arsenate was placed in a 2.00 M solution of ammonia, at equilibrium, 0.308 M of ammonia remains. If the Kf of tetraamminemanganese (II) ion is 250.0, Determine the Ksp of Manganese(II) arsenate Hint: You will have to figure out the Kspf of the overall chemical equation first, then solve for Ksp by using Kf and Kspfarrow_forwardNeed assistance with the following chemistry problem. I will upvote if satisifed. No AI response please. Thanks again.arrow_forward
- No AI response. I need assistance with the following chemistry problem. I will upvote if satisfied. Thank youarrow_forwardHello, I need assistance with this chemistry problem. It is regarding Clausius-Clapeyronarrow_forwardPlease correct answer and don't use hand rating and don't use Ai solutionarrow_forward
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