EBK MANUFACTURING ENGINEERING & TECHNOL
7th Edition
ISBN: 8220100793431
Author: KALPAKJIAN
Publisher: PEARSON
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Chapter 22, Problem 27QLP
Why are chemical stability and inertness important in cutting tools?
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3. What are the important characteristics of a cutting tool material?
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Chapter 22 Solutions
EBK MANUFACTURING ENGINEERING & TECHNOL
Ch. 22 - What are the major properties required of...Ch. 22 - What is the composition of a typical carbide tool?Ch. 22 - Why were cutting-tool inserts developed?Ch. 22 - Why are some tools coated? What are the common...Ch. 22 - Explain the applications and limitations of...Ch. 22 - List the major functions of cutting fluids.Ch. 22 - Why is toughness important for cutting-tool...Ch. 22 - Is the elastic modulus important for cutting-tool...Ch. 22 - Explain how cutting fluids penetrate the toolchip...Ch. 22 - List the methods by which cutting fluids are...
Ch. 22 - Describe the advantages and limitations of (a)...Ch. 22 - What is a cermet? What are its advantages?Ch. 22 - Explain the difference between M-series and...Ch. 22 - Why is cBN generally preferred over diamond for...Ch. 22 - What are the advantages to dry machining?Ch. 22 - Explain why so many different types of...Ch. 22 - Which tool-material properties are suitable for...Ch. 22 - Describe the reasons for and advantages of coating...Ch. 22 - Make a list of the alloying elements used in...Ch. 22 - As stated in Section 22.1, tool materials can have...Ch. 22 - Explain the economic impact of the trend shown in...Ch. 22 - Why does temperature have such an important effect...Ch. 22 - Ceramic and cermet cutting tools have certain...Ch. 22 - What precautions would you take in machining with...Ch. 22 - Can cutting fluids have any adverse effects in...Ch. 22 - Describe the trends you observe in Table 22.2.Ch. 22 - Why are chemical stability and inertness important...Ch. 22 - Titanium-nitride coatings on tools reduce the...Ch. 22 - Describe the necessary conditions for optimal...Ch. 22 - Negative rake angles generally are preferred for...Ch. 22 - Do you think that there is a relationship between...Ch. 22 - Make a survey of the technical literature, and...Ch. 22 - In Table 22.1, the last two properties listed...Ch. 22 - It has been stated that titanium-nitride coatings...Ch. 22 - Note in Fig. 22.1 that all tool materials,...Ch. 22 - Referring to Table 22.1, state which tool...Ch. 22 - Which of the properties listed in Table 22.1 is,...Ch. 22 - If a drill bit is intended only for woodworking...Ch. 22 - What are the consequences of a coating on a tool...Ch. 22 - Discuss the relative advantages and limitations of...Ch. 22 - Emulsion cutting fluids typically consist of 95%...Ch. 22 - List and explain the considerations involved in...Ch. 22 - Review the contents of Table 22.1. Plot several...Ch. 22 - Obtain data on the thermal properties of various...Ch. 22 - The first column in Table 22.2 shows 10 properties...Ch. 22 - Describe in detail your thoughts regarding the...Ch. 22 - One of the principal concerns with coolants is...Ch. 22 - How would you go about measuring the effectiveness...Ch. 22 - There are several types of cutting-tool materials...Ch. 22 - Assume that you are in charge of a laboratory for...Ch. 22 - Tool life could be greatly increased if an...Ch. 22 - List the concerns you would have if you needed to...
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- Question 3. a. A cast iron component for motorcycle is to be turned with machine settings of feed = 0.22 mm/rev, and speed = 100 m/min. The cutting tool is a carbide tip with a nose radius of 1.2 mm and the rai for the material at a cutting speed of 100 m/min is 1.3. Calculate the surface roughness for this cut. [6 marks]arrow_forwardI need answer within 20 minutes please please with my best wishesarrow_forwardThe results of machining steel with two grades of tool material are given below: Taylor's Exponent Cutting speed for 1(one) minuto Tool A B tool life metres/min 100 120 0.20 0.25 (i) For a 400 minute tool life, which tool is recommended and why? (ii) The tool changing time for the preferred tool is 15 minutes which cutting speed has to be chosen from the available speeds 45 m/min; 5 m/min.arrow_forward
- In a cutting test with 0.3 mm flank wear as tool failure criterion, a tool life of 10 min was obtained at a cutting velocity of 20 m/min. Taking tool life exponent as 0.25, the tool life in minutes at 40 m/min of cutting velocity will be?arrow_forwardDuring turning tests, using a cemented carbide tool resulted in a 1‑min tool life at a cutting speed = 4.8 m/s and a 22‑min tool life at a speed = 2.0 m/s. (a) Find the n and Carrow_forwardWhat is the approximate % change in the life, t, of the tool with zero rake angle used in orthogonal cutting when its clearance angle, a, is changed from 10 to 7 deg? (Hints Flank wear rate is proportional to cot a) (a) 30% increase (c) 70% increase (b) 30% decrease (d) 70% decreasearrow_forward
- Identify major sources of heat generated in Cutting toolarrow_forwardIn an orthogonal cutting test with a bar of 75 mm diameter is reduced to 73 mm by using a HSS tool with arake angle = 10o, following observations were made: length of the chip, lc = 69.44 mm, cutting ratio r =0.3, the horizontal component of the cutting force, FH = 1450 N, and the vertical component of the cuttingforce, FV = 850 N. The various parameters recorded in this cutting operation are: depth of cut, d = 2 mm;feed rate, f = 0.3 mm/rev, cutting speed, V = 60 m/min. Using Merchant’s theory calculate the following:1) Friction force along rake face2) Normal force acting on rake face3) Shear force along the shear plane4) Normal force acting on shear plane5) The percentage error in shear angle predicted by Merchant’s theory6) Shear velocity7) Chip velocity8) Total work done9) The shear work proportion out of the total work done10) The friction work proportion out of the total work donearrow_forward34 - The outside diameter of a cylinder made of titanium alloy is to be turned. The starting diameter is 400 mm and the length is 1100 mm. The feed is 0.35 mm/rev and the depth of cut is 2.5 mm. The cut will be made with a cemented carbide cutting tool whose Taylor tool life parameters are: n= 0.24 and C-450. Units for the Taylor equation are min for tool life and m/min for cutting speed. Compute the cutting speed that will allow the tool life to be just equal to the cutting time for this part. vT" = C . AD,L Tm %3D fv a) 325.8 m /min b) 275.8 m/min 226.6 m/min d) O 187.9 m/minarrow_forward
- what are the three basic parameters (cutting variables) in the machining process? how to calculate themarrow_forward3) The following data are available from orthogonal cutting experiment, Depth of cut t, = 0.13 mm, width of cut w = 2.5 mm, rake angle a = -5°, cutting speed v = 2 m/s, Chip thickness, t= 0.23 mm, cutting force, F. = 430 N, thrust force, F = 280 N. Determine the following: Shear angle Friction Coefficient u (using F= µ N) Shear Stress t,S Shear strain y on the shear plane. Power required to perform the operation. Gross power required if the efficiency of the machine is 85%. Specific Energy, Utarrow_forwardQuestion 2. The two sources of heat are (a) shearing in the primary shear plane and (b) friction at the tool-chip interface. What type of the tool wear or tool failure could be caused as a result of developing these heat sources on machining process? Explain your answer in accordance with following representation of tool wear. Insert cutting edgearrow_forward
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