![Chemistry & Chemical Reactivity](https://www.bartleby.com/isbn_cover_images/9781337399074/9781337399074_largeCoverImage.gif)
Concept explainers
(a)
Interpretation: The compound or ion of a second period element, that has formula and lewis structure analogous to given formula
Concept introduction: The elements belonging to the same group of periodic table have same number of electrons in their valence shell. Thus, their physical and chemical properties are also similar.
These elements can exist in similar oxidation state due to same number of valence electrons in the outermost shell. Hence, the elements of same group form compounds with same formula.
If two elements belongs to
However, the lighter elements of the group do not expand their octet while the heavier elements can expand their octet and form compounds with different oxidation numbers. So if the elements belong to group
So, the same number of valence electrons in outermost shell of the elements in same group is responsible for the similar chemical properties of these elements. Thus they also form compounds with same formula.
(b)
Interpretation: The compound or ion of a second period element, that has formula and lewis structure analogous to given formula
Concept introduction: The elements belonging to the same group of periodic table have same number of electrons in their valence shell. Thus, their physical and chemical properties are also similar.
These elements can exist in similar oxidation state due to same number of valence electrons in the outermost shell. Hence, the elements of same group form compounds with same formula.
If two elements belongs to
However, the lighter elements of the group do not expand their octet while the heavier elements can expand their octet and form compounds with different oxidation numbers. So if the elements belong to group
So, the same number of valence electrons in outermost shell of the elements in same group is responsible for the similar chemical properties of these elements. Thus they also form compounds with same formula.
(c)
Interpretation: The compound or ion of a second period element, that has formula and lewis structure analogous to given formula
Concept introduction: The elements belonging to the same group of periodic table have same number of electrons in their valence shell. Thus, their physical and chemical properties are also similar.
These elements can exist in similar oxidation state due to same number of valence electrons in the outermost shell. Hence, the elements of same group form compounds with same formula.
If two elements belongs to
However, the lighter elements of the group do not expand their octet while the heavier elements can expand their octet and form compounds with different oxidation numbers. So if the elements belong to group
So, the same number of valence electrons in outermost shell of the elements in same group is responsible for the similar chemical properties of these elements. Thus they also form compounds with same formula.
(d)
Interpretation: The compound or ion of a second period element, that has formula and lewis structure analogous to given formula
Concept introduction: The elements belonging to the same group of periodic table have same number of electrons in their valence shell. Thus, their physical and chemical properties are also similar.
These elements can exist in similar oxidation state due to same number of valence electrons in the outermost shell. Hence, the elements of same group form compounds with same formula.
If two elements belongs to
However, the lighter elements of the group do not expand their octet while the heavier elements can expand their octet and form compounds with different oxidation numbers. So if the elements belong to group
So, the same number of valence electrons in outermost shell of the elements in same group is responsible for the similar chemical properties of these elements. Thus they also form compounds with same formula.
![Check Mark](/static/check-mark.png)
Want to see the full answer?
Check out a sample textbook solution![Blurred answer](/static/blurred-answer.jpg)
Chapter 21 Solutions
Chemistry & Chemical Reactivity
- [In this question, there are multiple answers to type in a "fill-in-the-blank" fashion - in each case, type in a whole number.] Consider using Slater's Rules to calculate the shielding factor (S) for the last electron in silicon (Si). There will be electrons with a 0.35 S-multiplier, electrons with a 0.85 S-multiplier, and electrons with a 1.00 S-multiplier.arrow_forwardProvide the unknown for the given data.arrow_forwardDraw the Lewis structures of two methanol (CH3OH) molecules and depict hydrogenbonding between them with dashed lines. Show all lone pairs. Provide a thorough analysis to apply concept idea into other problems.arrow_forward
- Steps and explanation please.arrow_forwardHow could you distinguish between each pair of compounds below using IR? For each pair citeone bond and it’s frequency that you could use to distinguish between them. Please provide thorough analysis to apply into further problems.arrow_forwardSteps and explanation please.arrow_forward
- Provide the unknown for the given dataarrow_forwardProvide the unknown for the given data.arrow_forwardElectron Arrangement A. Fill in the following chart relating to levels, sublevels and orbitals. Levels (n) 1 Sublevels # of Orbitals per sublevel 2 3 4 # of Electrons per sublevel Total Electrons per level Complete: B. Answer the following questions related to levels, sublevels, orbitals and electrons. 1. How many sublevels are in energy level 2? 2. How many orbitals are in a 4f sublevel? 3. How many electrons can level 3 hold? 4. How many orbitals are in level 4? 5. How many electrons can sublevel 2p hold? 11arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningIntroduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285199047/9781285199047_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285869759/9781285869759_smallCoverImage.gif)