The halogen which has the highest bond dissociation enthalpy is to be stated. Concept introduction: The bond dissociation energy is the energy required to break one mole of the gas (in gaseous state) to give the separate atoms in gaseous state. As number of bond increase, length gets shorter and bond energy increases. Therefore, H − H bonds are fairly easy to break and makes hydrogen gas reactive. Nitrogen has a triple bond, which takes a lot of energy to break and is pretty much inert.

Question

I have a bottle of butanal that has been improperly used by lab workers. They allowed a traceamount NaOH (aq) to contaminate the bottle. What is now in my bottle of “butanal? What is the molecular name and functional group name? Draw the structure.

Answer 1

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 21, Problem 75PS

Interpretation Introduction

Interpretation: The halogen which has the highest bond dissociation enthalpy is to be stated.

Concept introduction: The bond dissociation energy is the energy required to break one mole of the gas (in gaseous state) to give the separate atoms in gaseous state.

As number of bond increase, length gets shorter and bond energy increases.

Therefore,

H−H bonds are fairly easy to break and makes hydrogen gas reactive.

Nitrogen has a triple bond, which takes a lot of energy to break and is pretty much inert.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

I have a bottle of butanal that has been improperly used by lab workers. They allowed a traceamount NaOH (aq) to contaminate the bottle. What is now in my bottle of “butanal? What is the molecular name and functional group name? Draw the structure.

Provide the missing information. *see image

First image: Why can't the molecule C be formed in those conditions Second image: Synthesis for lactone C its not an exam

Answer 2

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 21, Problem 75PS

Interpretation Introduction

Interpretation: The halogen which has the highest bond dissociation enthalpy is to be stated.

Concept introduction: The bond dissociation energy is the energy required to break one mole of the gas (in gaseous state) to give the separate atoms in gaseous state.

As number of bond increase, length gets shorter and bond energy increases.

Therefore,

H−H bonds are fairly easy to break and makes hydrogen gas reactive.

Nitrogen has a triple bond, which takes a lot of energy to break and is pretty much inert.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 3

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 21, Problem 75PS

Interpretation Introduction

Interpretation: The halogen which has the highest bond dissociation enthalpy is to be stated.

Concept introduction: The bond dissociation energy is the energy required to break one mole of the gas (in gaseous state) to give the separate atoms in gaseous state.

As number of bond increase, length gets shorter and bond energy increases.

Therefore,

H−H bonds are fairly easy to break and makes hydrogen gas reactive.

Nitrogen has a triple bond, which takes a lot of energy to break and is pretty much inert.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 4

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 21, Problem 75PS

Interpretation Introduction