Concept explainers
(a)
Interpretation: The given reaction equation has to be completed and balanced.
Concept introduction: A chemical equation consists of reactants and products. The two are separated by an arrow. Each substances of reactants and products are separated from other by a plus sign. The reactants lies on left hand side while products lies on right hand side of the reaction.
A balanced chemical equation occurs when the number of atoms in reactant side is equal to the number of atoms in the product side.
(b)
Interpretation: The given reaction equation has to be completed and balanced.
Concept introduction: A chemical equation consists of reactants and products. The two are separated by an arrow. Each substances of reactants and products are separated from other by a plus sign. The reactants lies on left hand side while products lies on right hand side of the reaction.
A balanced chemical equation occurs when the number of atoms in reactant side is equal to the number of atoms in the product side.
(c)
Interpretation: The given reaction equation has to be completed and balanced.
Concept introduction: A chemical equation consists of reactants and products. The two are separated by an arrow. Each substances of reactants and products are separated from other by a plus sign. The reactants lies on left hand side while products lies on right hand side of the reaction.
A balanced chemical equation occurs when the number of atoms in reactant side is equal to the number of atoms in the product side.
(d)
Interpretation: The given reaction equation has to be completed and balanced.
Concept introduction: A chemical equation consists of reactants and products. The two are separated by an arrow. Each substances of reactants and products are separated from other by a plus sign. The reactants lies on left hand side while products lies on right hand side of the reaction.
A balanced chemical equation occurs when the number of atoms in reactant side is equal to the number of atoms in the product side.
(e)
Interpretation: The given reaction equation has to be completed and balanced.
Concept introduction: A chemical equation consists of reactants and products. The two are separated by an arrow. Each substances of reactants and products are separated from other by a plus sign. The reactants lies on left hand side while products lies on right hand side of the reaction.
A balanced chemical equation occurs when the number of atoms in reactant side is equal to the number of atoms in the product side.
(f)
Interpretation: The given reaction equation has to be completed and balanced.
Concept introduction: A chemical equation consists of reactants and products. The two are separated by an arrow. Each substances of reactants and products are separated from other by a plus sign. The reactants lies on left hand side while products lies on right hand side of the reaction.
A balanced chemical equation occurs when the number of atoms in reactant side is equal to the number of atoms in the product side.
(g)
Interpretation: The given reaction equation has to be completed and balanced.
Concept introduction: A chemical equation consists of reactants and products. The two are separated by an arrow. Each substances of reactants and products are separated from other by a plus sign. The reactants lies on left hand side while products lies on right hand side of the reaction.
A balanced chemical equation occurs when the number of atoms in reactant side is equal to the number of atoms in the product side.
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Chapter 21 Solutions
Chemistry & Chemical Reactivity
- 2) Draw the correct chemical structure (using line-angle drawings / "line structures") from their given IUPAC name: a. (E)-1-chloro-3,4,5-trimethylhex-2-ene b. (Z)-4,5,7-trimethyloct-4-en-2-ol C. (2E,6Z)-4-methylocta-2,6-dienearrow_forwardපිපිම Draw curved arrows to represent the flow of electrons in the reaction on the left Label the reactants on the left as either "Acid" or "Base" (iii) Decide which direction the equilibrium arrows will point in each reaction, based on the given pk, values (a) + H-O H 3-H + (c) H" H + H****H 000 44-00 NH₂ (e) i Дон OH Ө NHarrow_forward3) Label the configuration in each of the following alkenes as E, Z, or N/A (for non-stereogenic centers). 00 E 000 N/A E Br N/A N/A (g) E N/A OH E (b) Oz N/A Br (d) 00 E Z N/A E (f) Oz N/A E (h) Z N/Aarrow_forward
- 6) Fill in the missing Acid, pKa value, or conjugate base in the table below: Acid HCI Approximate pK, -7 Conjugate Base H-C: Hydronium (H₂O') -1.75 H-O-H Carboxylic Acids (RCOOH) Ammonium (NH4) 9.24 Water (H₂O) H-O-H Alcohols (ROH) RO-H Alkynes R--H Amines 25 25 38 HOarrow_forward5) Rank the following sets of compounds in order of decreasing acidity (most acidic to least acidic), and choose the justification(s) for each ranking. (a) OH V SH я вон CH most acidic (lowst pKa) least acidic (highest pKa) Effect(s) Effect(s) Effect(s) inductive effect O inductive effect O inductive effect electronegativity electronegativity O electronegativity resonance polarizability resonance polarizability O resonance O polarizability hybridization Ohybridization O hybridization оarrow_forwardHow negatively charged organic bases are formed.arrow_forward
- Nonearrow_forward1) For the following molecules: (i) Label the indicated alkenes as either cis (Z), trans (E), or N/A (for non-stereogenic centers) by bubbling in the appropriate label on the molecule. (ii) Complete the IUPAC name located below the structure (HINT: Put the letter of the configuration in parentheses at the beginning of the name!) E z N/A ()-3,4,6-trimethylhept-2-ene E Oz O N/A ()-3-ethyl-1-fluoro-4-methylhex-3-ene E -+- N/A Me )-2,3-dimethylpent-2-ene (d) (b) E O N/A Br ()-5-bromo-1-chloro-3-ethyloct-4-ene ОЕ Z N/A Et (___)-3-ethyl-4-methylhex-3-ene E (f) Oz N/A z N/A HO (4.7)-4-(2-hydroxyethyl)-7-methylnona-4,7-dien-2-onearrow_forwardO 9:21AM Tue Mar 4 ## 64% Problem 51 of 15 Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. H :0: CI. AI :CI: :CI: Cl AI Select to Add Arrows Select to Add Arrows O: Cl :CI: :0: H CI: CI CO Select to Add Arrows Select to Add Arrows :O: CI :0: Cl. 10: AIarrow_forward
- (i) Draw in the missing lone pair(s) of electrons of the reactants on the left (ii) Draw (curved) arrows to show the flow of electrons in the acid/base reaction on the left (iii) Draw the products of the acid/base on the right (iv) Select the correct label for each product as either "conjugate acid" or "conjugate base" (a) JOH OH NH₂ acid base (b) De "H conjugate acid conjugate acid conjugate base conjugate base acid base conjugate acid conjugate base conjugate acid conjugate base acid basearrow_forwardCould someone answer this NMR and explain please Comment on the general features of the 1H-NMR spectrum of isoamyl ester provided below.arrow_forwardMacmillan Learning Draw the acyl chloride that would give the ketone shown using the Friedel-Crafts acylation reaction. Select Draw Templates More с H о Cl 2Q Erase AICI₂arrow_forward
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