Chapter 21, Problem 44R

To determine

To Complete:The table by finding the type of solution; whether it is unsaturated or saturated or supersaturated solution.

Explanation of Solution

Introduction:

A saturated solution is a solution that contains all of the solute that it can hold at a given temperature.

a.) 32.0 g of Copper sulfate $\left({\text{CuSO}}_{\text{4}}\right)$ can dissolve in 100 g of water at 20 $\text{°C}$ ; hence no more solute can be added. So, it forms a saturated solution.

b.) 34.0 g of Potassium chloride (KCl) can dissolve in 100 g of water at 20 $\text{°C}$ ; hence no more solute can be added. So, out of 36.0 g solute only 34.0 g will dissolve and forms a saturated solution.

c.) 31.6 g of Potassium nitrate $\left({\text{KNO}}_{\text{3}}\right)$ can dissolve in 100 g of water at 20 $\text{°C}$ ; hence no more solute can be added and so it forms saturated solution.

d.) 95.9 g of Sodium chlorate $\left({\text{NaClO}}_{\text{3}}\right)$ can dissolve in 100 g of water at 20 $\text{°C}$ ; but in given question only 92.9 g is added.Hence, more solute (3.0 g) can be added and forms a unsaturated solution.

Conclusion:

Thus, given table can be completed by filling following answers:

a. Saturated solution.

b. Saturated solution.

c. Saturated solution.

d. Unsaturated solution.