Pearson eText Fundamentals of General, Organic, and Biological Chemistry -- Instant Access (Pearson+)
Pearson eText Fundamentals of General, Organic, and Biological Chemistry -- Instant Access (Pearson+)
8th Edition
ISBN: 9780135213759
Author: John McMurry, David Ballantine
Publisher: PEARSON+
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Chapter 20.6, Problem 20.16P
Interpretation Introduction

Interpretation:

The structure of two monosaccharides formed by the hydrolysis of cellobiose have to be given along with their names.

Concept introduction:

Cellobiose is a disaccharide composed of two β-D-glucose by β-1,4 glycosidic linkage.

The hydrolysis of Disaccharides breaks the glycosidic linkages and produces their monosaccharides.

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Macmillan Learning The phosphorylation of glucose to glucose 6-phosphate is the initial step in the catabolism of glucose. The direct phosphorylation of glucose by P, is described by the equation Glucose + P ← glucose 6-phosphate + H₂O AG = 13.8 kJ/mol Coupling ATP hydrolysis to glucose phosphorylation makes thermodynamic sense, but consider how the coupling might take place. Given that coupling requires a common intermediate, one conceivable mechanism is to use ATP hydrolysis to raise the intracellular concentration of Pi. The increase in P; concentration would drive the unfavorable phosphorylation of glucose by Pi- Is increasing the P; concentration a reasonable way to couple ATP hydrolysis and glucose phosphorylation? No. The phosphate salts of divalent cations would be present in excess and precipitate out. Yes. Increasing the concentration of P; would decrease K'eq and shift equilibrium to the right. Yes. The extra ATP hydrolysis would provide enough free energy to drive the…
The phosphorylation of glucose to glucose 6-phosphate is the initial step in the catabolism of glucose. The direct phosphorylation of glucose by P, is described by the equation Glucose + P → glucose 6-phosphate + H₂O AG' = 13.8 kJ/mol In principle, at least, one way to increase the concentration of glucose 6-phosphate (G6P) is to drive the equilibrium reaction to the right by increasing the intracellular concentrations of glucose and Pj. The maximum solubility of glucose is less than 1 M, and the normal physiological concentration of G6P is 250 μM. Assume a fixed concentration of P, at 4.8 mM. The calculated value of K'cq is 4.74 × 10-³ M-¹. Calculate the intracellular concentration of glucose when the equilibrium concentration of glucose 6-phosphate is 250 μM, the normal physiological concentration. [glucose] = 10.99 Correct Answer Would increasing the concentration of glucose be a physiologically reasonable way to increase the concentration of G6P? No. Because the concentration of P,…
Calculate the equilibrium constant for the phosphorylation of glucose to glucose 6-phosphate at 37.0 °C. K'eq = M-' In the rat hepatocyte, the physiological concentrations of glucose and P, are maintained at approximately 4.8 mM. What is the equilibrium concentration of glucose 6-phosphate (G6P) obtained by the direct phosphorylation of glucose by P.? [G6P] = Does this reaction represent a reasonable metabolic step for the catabolism of glucose? Why or why not? Yes, because the value of AG" is positive. No, because the K'eq is too large for the reaction to proceed in the forward direction. Yes, because AG is negative at the calculated value of K'eq No, because [G6P] is likely to be higher than the calculated value. M

Chapter 20 Solutions

Pearson eText Fundamentals of General, Organic, and Biological Chemistry -- Instant Access (Pearson+)

Ch. 20.4 - Prob. 20.12PCh. 20.4 - Prob. 20.13PCh. 20.4 - Prob. 20.1CIAPCh. 20.4 - Prob. 20.2CIAPCh. 20.4 - All cells in your body contain glycoproteins...Ch. 20.5 - Draw the structure of the and anomers that...Ch. 20.6 - Prob. 20.15PCh. 20.6 - Prob. 20.16PCh. 20.6 - Prob. 20.17KCPCh. 20.7 - Prob. 20.4CIAPCh. 20.7 - Prob. 20.5CIAPCh. 20.7 - Prob. 20.6CIAPCh. 20.7 - Prob. 20.7CIAPCh. 20.7 - Prob. 20.18PCh. 20.7 - Prob. 20.19PCh. 20.7 - Prob. 20.8CIAPCh. 20.7 - Prob. 20.9CIAPCh. 20.7 - Prob. 20.10CIAPCh. 20 - During the digestion of starch from potatoes, the...Ch. 20 - Prob. 20.21UKCCh. 20 - Consider the trisaccharide A, B, C shown in...Ch. 20 - Hydrolysis of both glycosidic bonds in the...Ch. 20 - Prob. 20.24UKCCh. 20 - Are one or more of the disaccharides maltose,...Ch. 20 - Prob. 20.26UKCCh. 20 - Prob. 20.27UKCCh. 20 - Prob. 20.28APCh. 20 - What is the family-name ending for a sugar?Ch. 20 - Prob. 20.30APCh. 20 - Classify the four carbohydrates (a)(d) by...Ch. 20 - Prob. 20.32APCh. 20 - How many chiral carbon atoms are there in each of...Ch. 20 - Prob. 20.34APCh. 20 - Prob. 20.35APCh. 20 - Name four important monosaccharides and tell where...Ch. 20 - Prob. 20.37APCh. 20 - Prob. 20.38APCh. 20 - What is the structural relationship between...Ch. 20 - Prob. 20.40APCh. 20 - In Section 15.6, you saw that aldehydes react with...Ch. 20 - Sucrose and D-glucose rotate plane-polarized light...Ch. 20 - Prob. 20.43APCh. 20 - Prob. 20.44APCh. 20 - Prob. 20.45APCh. 20 - What is mutarotation? Do all chiral molecules do...Ch. 20 - What are anomers, and how do the anomers of a...Ch. 20 - What is the structural difference between the ...Ch. 20 - D-Gulose, an aldohexose isomer of glucose, has the...Ch. 20 - Prob. 20.50APCh. 20 - In its open-chain form, D-altrose has the...Ch. 20 - Prob. 20.52APCh. 20 - Prob. 20.53APCh. 20 - Prob. 20.54APCh. 20 - Prob. 20.55APCh. 20 - What is the structural difference between a...Ch. 20 - What are glycosides, and how can they be formed?Ch. 20 - Prob. 20.58APCh. 20 - Prob. 20.59APCh. 20 - Give the names of three important disaccharides....Ch. 20 - Lactose and maltose are reducing disaccharides,...Ch. 20 - Amylose (a form of starch) and cellulose are both...Ch. 20 - Prob. 20.63APCh. 20 - Prob. 20.64APCh. 20 - Prob. 20.65APCh. 20 - Gentiobiose, a rare disaccharide found in saffron,...Ch. 20 - Prob. 20.67APCh. 20 - Prob. 20.68APCh. 20 - Prob. 20.69APCh. 20 - Amylopectin (a form of starch) and glycogen are...Ch. 20 - What is the physiological purpose of starch in a...Ch. 20 - Prob. 20.72APCh. 20 - Prob. 20.73APCh. 20 - Prob. 20.74CPCh. 20 - Prob. 20.75CPCh. 20 - Prob. 20.76CPCh. 20 - Prob. 20.77CPCh. 20 - Prob. 20.78CPCh. 20 - Write the open-chain structure of the only...Ch. 20 - Prob. 20.80CPCh. 20 - Prob. 20.81CPCh. 20 - When a person cannot digest galactose, its reduced...Ch. 20 - Describe the differences between mono-, di-, and...Ch. 20 - Prob. 20.84CPCh. 20 - Prob. 20.85CPCh. 20 - Many people who are lactose intolerant can eat...Ch. 20 - Prob. 20.87GPCh. 20 - Prob. 20.88GPCh. 20 - Prob. 20.89GP
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