Concept explainers
Interpretation:
The question asks one to write the equations corresponding to the oxidation of a primary alcohol and a secondary alcohol. Also one needs to specify the structure of each alcohol and the principal products of oxidation.
Concept Introduction:
Monohydric alcohols can be categorized into three types as primary, secondary and tertiary alcohols.
AS shown above in primary alcohols carbon with the −OH group is bonded to only one carbon whereas in secondary alcohols, carbon with the −OH group is bonded to two other carbon atoms. In tertiary alcohols(not shown here), carbon with the −OH group is bonded to three other carbon atoms.
In the alcohols the −OH bond is polarized placing partially negative charge on O atom while placing a partially positive charge on the alkyl carbon atom of the R-OH bond. Hence due to the inter molecular hydrogen bonds formed between alcohol molecules, their boiling points have higher values compared to the
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Chapter 20 Solutions
Introductory Chemistry: Foundation - Text (Looseleaf)
- 2. Please fill in missing reactants, reagents, reaction conditions, or products in the provided blank boxes OMe ...-CF2-CF2-CF2-CF2-CF2-...arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardI don't understand what to put for final step. Does that just mean termination? And would a radical form when I add bromine to ch2 between the rings?arrow_forward
- H2SO4 (cat.), H₂O 100 °C NH₂arrow_forwardX Draw the major products of the elimination reaction below. If elimination would not occur at a significant rate, check the box under the drawing area instead. ది www. Cl + OH Elimination will not occur at a significant rate. Click and drag to start drawing a structure.arrow_forwardNonearrow_forward
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