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Interpretation:
The IUPAC names of the given alcohol and whether it is primary, secondary or tertiary should be determined.
Concept Introduction:
When alcohol (having hydroxyl group) is attached to a primary carbon atom (carbon atom to which one carbon atom is attached) then such alcohol is said to be a primary alcohol.
When alcohol (having hydroxyl group) is attached to a secondary carbon atom (carbon atom to which two carbon atoms are attached) then such alcohol is said to be a secondary alcohol.
When alcohol (having hydroxyl group) is attached to a tertiary carbon atom (carbon atom to which three carbon atoms are attached) then such alcohol is said to be a tertiary alcohol.
In order to give the IUPAC name to the alcohol following steps are followed:
1. The parent (longest)
2. The ending of the parent chain from alkane (-e) is changed to -ol and the number is used to locate the -OH group of alcohol.
3. Name should be written in alphabetical order and numbering should be done in such a way that hydroxy group gets lowest number.
4. Configuration should be specified is there exist any cis-trans isomerism.
Interpretation:
The IUPAC names of the given alcohol and whether it is primary, secondary or tertiary should be determined.
Concept Introduction:
When alcohol (having hydroxyl group) is attached to a primary carbon atom (carbon atom to which one carbon atom is attached) then such alcohol is said to be a primary alcohol.
When alcohol (having hydroxyl group) is attached to a secondary carbon atom (carbon atom to which two carbon atoms are attached) then such alcohol is said to be a secondary alcohol.
When alcohol (having hydroxyl group) is attached to a tertiary carbon atom (carbon atom to which three carbon atoms are attached) then such alcohol is said to be a tertiary alcohol.
In order to give the IUPAC name to the alcohol following steps are followed:
1. The parent (longest) alkane chain is identified.
2. The ending of the parent chain from alkane (-e) is changed to -ol and the number is used to locate the -OH group of alcohol.
3. Name should be written in alphabetical order and numbering should be done in such a way that hydroxy group gets lowest number.
4. Configuration should be specified is there exist any cis-trans isomerism.
Interpretation:
The IUPAC names of the given alcohol and whether it is primary, secondary or tertiary should be determined.
Concept Introduction:
When alcohol (having hydroxyl group) is attached to a primary carbon atom (carbon atom to which one carbon atom is attached) then such alcohol is said to be a primary alcohol.
When alcohol (having hydroxyl group) is attached to a secondary carbon atom (carbon atom to which two carbon atoms are attached) then such alcohol is said to be a secondary alcohol.
When alcohol (having hydroxyl group) is attached to a tertiary carbon atom (carbon atom to which three carbon atoms are attached) then such alcohol is said to be a tertiary alcohol.
In order to give the IUPAC name to the alcohol following steps are followed:
1. The parent (longest) alkane chain is identified.
2. The ending of the parent chain from alkane (-e) is changed to -ol and the number is used to locate the -OH group of alcohol.
3. Name should be written in alphabetical order and numbering should be done in such a way that hydroxy group gets lowest number.
4. Configuration should be specified is there exist any cis-trans isomerism.
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Chapter 20 Solutions
Introductory Chemistry: Foundation - Text (Looseleaf)
- 5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3arrow_forwardShow work. don't give Ai generated solution. How many carbons and hydrogens are in the structure?arrow_forward13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…arrow_forward
Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning