(a) Interpretation: The systematic names of the given unsaturated hydrocarbon should be determined. Concept Introduction: The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne . In order to give the name to the unsaturated hydrocarbon following steps are followed: 1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected. 2. While writing the name of alkene, the suffix “ane” of the corresponding alkane is replaced by “ene”. 3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number. 4. Hyphen is used to connect the number to the name. For number of carbons atoms in alkane chain, the prefix is given as: Carbon-1meth Carbon-2eth Carbon-3prop Carbon-4but Carbon-5pent Carbon-6hex Carbon-7hept Carbon-8oct Carbon-9non Carbon-10dec.

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Answer 1

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 12

So, the IUPAC name will be: 4-ethyl-3-methyloct-1-yne.

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3. Consider the compounds below and determine if they are aromatic, antiaromatic, or non-aromatic. In case of aromatic or anti-aromatic, please indicate number of I electrons in the respective systems. (Hint: 1. Not all lone pair electrons were explicitly drawn and you should be able to tell that the bonding electrons and lone pair electrons should reside in which hybridized atomic orbital 2. You should consider ring strain- flexibility and steric repulsion that facilitates adoption of aromaticity or avoidance of anti- aromaticity) H H N N: NH2 N Aromaticity (Circle) Aromatic Aromatic Aromatic Aromatic Aromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic aromatic TT electrons Me H Me Aromaticity (Circle) Aromatic Aromatic Aromatic Aromatic Aromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic aromatic πT electrons H HH…

The given structure is:

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 11

The parent chain in the given structure is of 8-carbon atoms so, prefix will be oct. Numbering is done in such a way that the multiple bond that is triple bond gets lower number that is 1 for triple bond. The substituent on 3 position is methyl and on 4 position is ethyl.

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 12

4-ethyl-3-methyloct-1-yne.

Explanation of Solution

The given structure is:

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 11

The parent chain in the given structure is of 8-carbon atoms so, prefix will be oct. Numbering is done in such a way that the multiple bond that is triple bond gets lower number that is 1 for triple bond. The substituent on 3 position is methyl and on 4 position is ethyl.

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 12

4-ethyl-3-methyloct-1-yne.

Explanation of Solution

The given structure is:

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 11

The parent chain in the given structure is of 8-carbon atoms so, prefix will be oct. Numbering is done in such a way that the multiple bond that is triple bond gets lower number that is 1 for triple bond. The substituent on 3 position is methyl and on 4 position is ethyl.

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 12

So, the IUPAC name will be: 4-ethyl-3-methyloct-1-yne.

Want to see more full solutions like this?

The parent chain in the given structure is of 8-carbon atoms so, prefix will be oct. Numbering is done in such a way that the multiple bond that is triple bond gets lower number that is 1 for triple bond. The substituent on 3 position is methyl and on 4 position is ethyl.

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 12

So, the IUPAC name will be: 4-ethyl-3-methyloct-1-yne.

Answer 6

Chapter 20, Problem 144CP

Interpretation Introduction

(a)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkene, the suffix “ane” of the corresponding alkane is replaced by “ene”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Expert Solution

Answer to Problem 144CP

2-methylbut-1-ene.

Explanation of Solution

The given structure is:

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 1

The parent chain in the given structure is of 4-carbon atoms so, prefix will be but. Numbering is done in such a way that the multiple bond that is double bond gets lower number that is 1 for double bond and the substituent on 2 position is methyl.

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 2

So, the IUPAC name will be: 2-methylbut-1-ene.

Answer 7

Chapter 20, Problem 144CP

Interpretation Introduction

(a)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkene, the suffix “ane” of the corresponding alkane is replaced by “ene”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Answer 8

Expert Solution

Answer to Problem 144CP

2-methylbut-1-ene.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The given structure is:

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 1

The parent chain in the given structure is of 4-carbon atoms so, prefix will be but. Numbering is done in such a way that the multiple bond that is double bond gets lower number that is 1 for double bond and the substituent on 2 position is methyl.

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 2

So, the IUPAC name will be: 2-methylbut-1-ene.

Answer 13

Interpretation Introduction

(b)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkene, the suffix “ane” of the corresponding alkane is replaced by “ene”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Expert Solution

Answer to Problem 144CP

2, 4-dimethylpent-1, 4-diene.

Explanation of Solution

The given structure is:

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 3

The parent chain in the given structure is of 5-carbon atoms so, prefix will be pent. Numbering is done in such a way that the multiple bond that is double bond gets lower number that is 1 and 4 for double bond and the substituent on 2 and 4 position is methyl.

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 4

So, the IUPAC name will be: 2, 4-dimethylpent-1, 4-diene.

Answer 14

Interpretation Introduction

(b)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkene, the suffix “ane” of the corresponding alkane is replaced by “ene”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Answer 15

Expert Solution

Answer to Problem 144CP

2, 4-dimethylpent-1, 4-diene.

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

The given structure is:

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 3

The parent chain in the given structure is of 5-carbon atoms so, prefix will be pent. Numbering is done in such a way that the multiple bond that is double bond gets lower number that is 1 and 4 for double bond and the substituent on 2 and 4 position is methyl.

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 4

So, the IUPAC name will be: 2, 4-dimethylpent-1, 4-diene.

Answer 20

Interpretation Introduction

(c)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkene, the suffix “ane” of the corresponding alkane is replaced by “ene”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Expert Solution

Answer to Problem 144CP

6-ethyl-2-methyloct-4-ene.

Explanation of Solution

The given structure is:

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 5

The parent chain in the given structure is of 5-carbon atoms so, prefix will be oct. Numbering is done in such a way that the multiple bond that is double bond gets lower number that is 4 for double bond and the substituent on 2 position is methyl and on 6 position is ethyl.

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 6

So, the IUPAC name will be: 6-ethyl-2-methyloct-4-ene.

Answer 21

Interpretation Introduction

(c)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkene, the suffix “ane” of the corresponding alkane is replaced by “ene”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Answer 22

Expert Solution

Answer to Problem 144CP

6-ethyl-2-methyloct-4-ene.

Answer 23

Expert Solution

Answer 24

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

The given structure is:

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 5

The parent chain in the given structure is of 5-carbon atoms so, prefix will be oct. Numbering is done in such a way that the multiple bond that is double bond gets lower number that is 4 for double bond and the substituent on 2 position is methyl and on 6 position is ethyl.

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 6

So, the IUPAC name will be: 6-ethyl-2-methyloct-4-ene.

Answer 27

Interpretation Introduction

(d)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkyne, the suffix “ane” of the corresponding alkane is replaced by “yne”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Expert Solution

Answer to Problem 144CP

3-bromohept-1-yne.

Explanation of Solution

The given structure is:

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 7

The parent chain in the given structure is of 7-carbon atoms so, prefix will be hept. Numbering is done in such a way that the multiple bond that is triple bond gets lower number that is 1 for triple bond. The substituent on 3 position is bromo.

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 8

So, the IUPAC name will be: 3-bromohept-1-yne.

Answer 28

Interpretation Introduction

(d)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkyne, the suffix “ane” of the corresponding alkane is replaced by “yne”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Answer 29

Expert Solution

Answer to Problem 144CP

3-bromohept-1-yne.

Answer 30

Expert Solution

Answer 31

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

The given structure is:

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 7

The parent chain in the given structure is of 7-carbon atoms so, prefix will be hept. Numbering is done in such a way that the multiple bond that is triple bond gets lower number that is 1 for triple bond. The substituent on 3 position is bromo.

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 8

So, the IUPAC name will be: 3-bromohept-1-yne.

Answer 34

Interpretation Introduction

(e)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkyne, the suffix “ane” of the corresponding alkane is replaced by “yne”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Expert Solution

Answer to Problem 144CP

7-chloro-2, 5, 5-trimethylhept-3-yne.

Explanation of Solution

The given structure is:

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 9

The parent chain in the given structure is of 7-carbon atoms so, prefix will be hept. Numbering is done in such a way that the multiple bond that is triple bond gets lower number that is 3 for triple bond. The substituent on 2 and 5 position is methyl and on 7 position is chloro.

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 10

So, the IUPAC name will be: 7-chloro-2, 5, 5-trimethylhept-3-yne.

Answer 35

Interpretation Introduction

(e)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkyne, the suffix “ane” of the corresponding alkane is replaced by “yne”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Answer 36

Expert Solution

Answer to Problem 144CP

7-chloro-2, 5, 5-trimethylhept-3-yne.

Answer 37

Expert Solution

Answer 38

Expert Solution

Answer 39

Expert Solution

Answer 40

Explanation of Solution

The given structure is:

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 9

The parent chain in the given structure is of 7-carbon atoms so, prefix will be hept. Numbering is done in such a way that the multiple bond that is triple bond gets lower number that is 3 for triple bond. The substituent on 2 and 5 position is methyl and on 7 position is chloro.

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 10

So, the IUPAC name will be: 7-chloro-2, 5, 5-trimethylhept-3-yne.

Answer 41

Interpretation Introduction

(f)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkyne, the suffix “ane” of the corresponding alkane is replaced by “yne”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Expert Solution

Answer to Problem 144CP

4-ethyl-3-methyloct-1-yne.

Explanation of Solution

The given structure is:

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 11

The parent chain in the given structure is of 8-carbon atoms so, prefix will be oct. Numbering is done in such a way that the multiple bond that is triple bond gets lower number that is 1 for triple bond. The substituent on 3 position is methyl and on 4 position is ethyl.

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 12

So, the IUPAC name will be: 4-ethyl-3-methyloct-1-yne.

Answer 42

Interpretation Introduction

(f)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkyne, the suffix “ane” of the corresponding alkane is replaced by “yne”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Answer 43

Expert Solution

Answer to Problem 144CP

4-ethyl-3-methyloct-1-yne.

Answer 44

Expert Solution

Answer 45

Expert Solution

Answer 46

Expert Solution

Answer 47

Explanation of Solution

The given structure is:

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 11

The parent chain in the given structure is of 8-carbon atoms so, prefix will be oct. Numbering is done in such a way that the multiple bond that is triple bond gets lower number that is 1 for triple bond. The substituent on 3 position is methyl and on 4 position is ethyl.

Introductory Chemistry: Foundation - Text (Looseleaf), Chapter 20, Problem 144CP , additional homework tip 12

So, the IUPAC name will be: 4-ethyl-3-methyloct-1-yne.