General, Organic, and Biological Chemistry - 4th edition
4th Edition
ISBN: 9781259883989
Author: by Janice Smith
Publisher: McGraw-Hill Education
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Question
Chapter 20, Problem 63P
Interpretation Introduction
Interpretation:
A segment of the polysaccharide formed by 3 galactose units joined together in 1-4 − α − linkages needs to be drawn.
Concept introduction:
1-4 − α − linkages are formed due to condensation reaction of a hydroxyl group on fourth carbon atom of one sugar with the anomeric first carbon of another sugar. β sign is given due to the position of the bonding hydroxyl group of anomeric carbon atom, which is below the ring.
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Students have asked these similar questions
. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the
molecule depicted below.
Bond B
2°C. +2°C. < cleavage
Bond A
• CH3 + 26. t cleavage
2°C• +3°C•
Bond C
Cleavage
CH3 ZC
'2°C. 26.
E
Strongest
3°C. 2C.
Gund
Largest
BDE
weakest bond
In that molecule
a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in
appropriate boxes.
Weakest
C bond
Produces
A
Weakest
Bond
Most
Strongest
Bond
Stable radical
Strongest Gund
produces least stable
radicals
b. (4pts) Consider the relative stability of all cleavage products that form when bonds A,
B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B,
and C are all carbon radicals.
i. Which ONE cleavage product is the most stable? A condensed or bond line
representation is fine.
人
8°C. formed in
bound C
cleavage
ii. Which ONE cleavage product is the least stable? A condensed or bond line
representation is fine.
methyl radical
•CH3
formed in
bund A Cleavage
Which carbocation is more stable?
Are the products of the given reaction correct? Why or why not?
Chapter 20 Solutions
General, Organic, and Biological Chemistry - 4th edition
Ch. 20.1 - Label the hemiacetal carbonthe carbon bonded to...Ch. 20.2 - Prob. 20.1PPCh. 20.2 - Prob. 20.2PCh. 20.2 - Prob. 20.3PCh. 20.2 - Prob. 20.4PCh. 20.2 - Prob. 20.5PCh. 20.2 - Prob. 20.2PPCh. 20.2 - Prob. 20.6PCh. 20.2 - Prob. 20.7PCh. 20.3 - Prob. 20.8P
Ch. 20.3 - Prob. 20.3PPCh. 20.3 - Prob. 20.4PPCh. 20.4 - Prob. 20.5PPCh. 20.4 - Prob. 20.6PPCh. 20.4 - Prob. 20.9PCh. 20.4 - Prob. 20.10PCh. 20.5 - Prob. 20.7PPCh. 20.5 - Prob. 20.8PPCh. 20.5 - Lactose contains both an acetal and a hemiacetal....Ch. 20.5 - Prob. 20.12PCh. 20.5 - Prob. 20.13PCh. 20.5 - Prob. 20.14PCh. 20.5 - Prob. 20.15PCh. 20.6 - Prob. 20.16PCh. 20.6 - Prob. 20.17PCh. 20.7 - Prob. 20.18PCh. 20.7 - Prob. 20.19PCh. 20.8 - Prob. 20.20PCh. 20 - Prob. 21PCh. 20 - Prob. 22PCh. 20 - Prob. 23PCh. 20 - Prob. 24PCh. 20 - Prob. 25PCh. 20 - Prob. 26PCh. 20 - Prob. 27PCh. 20 - Prob. 28PCh. 20 - Prob. 29PCh. 20 - Prob. 30PCh. 20 - Prob. 31PCh. 20 - Prob. 32PCh. 20 - Prob. 33PCh. 20 - Prob. 34PCh. 20 - Prob. 35PCh. 20 - Prob. 36PCh. 20 - Prob. 37PCh. 20 - Prob. 38PCh. 20 - Prob. 39PCh. 20 - Prob. 40PCh. 20 - Prob. 41PCh. 20 - Prob. 42PCh. 20 - Prob. 43PCh. 20 - Prob. 44PCh. 20 - Prob. 45PCh. 20 - Prob. 46PCh. 20 - What product is formed when each compound is...Ch. 20 - What product is formed when each compound is...Ch. 20 - Prob. 49PCh. 20 - Prob. 50PCh. 20 - Prob. 51PCh. 20 - Prob. 52PCh. 20 - Prob. 53PCh. 20 - Prob. 54PCh. 20 - Prob. 55PCh. 20 - Prob. 56PCh. 20 - Prob. 57PCh. 20 - Prob. 58PCh. 20 - Prob. 59PCh. 20 - Prob. 60PCh. 20 - Prob. 61PCh. 20 - Prob. 62PCh. 20 - Prob. 63PCh. 20 - Prob. 64PCh. 20 - Prob. 65PCh. 20 - Prob. 66PCh. 20 - Prob. 67PCh. 20 - Prob. 68PCh. 20 - Prob. 69PCh. 20 - Prob. 70PCh. 20 - Prob. 71PCh. 20 - Prob. 72PCh. 20 - Prob. 73PCh. 20 - Prob. 74PCh. 20 - Prob. 75PCh. 20 - Prob. 76PCh. 20 - Prob. 77PCh. 20 - Prob. 78PCh. 20 - Prob. 79CPCh. 20 - Prob. 80CP
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