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Concept explainers
(a)
Interpretation:
The acetal and hemiacetal in sophorose needs to be labeled.
Concept Introduction:
In a hemiacetal, an alcohol and ether attached to the same carbon.
A hemiacetal with an alcohol forms an acetal.
(b)
Interpretation:
Each monosaccharide ring should be numbered.
Concept Introduction:
Monosaccharides or simple sugars are the simplest carbohydrates. Generally, have three to six carbon atoms in achain, with a carbonyl group at either the terminal carbon, numbered C1, or the carbon adjacent to it, numbered C2.
(c)
Interpretation:
Glycosidic linkage needs to be classified as a or β and its location should be designated using numbers.
Concept Introduction:
Disaccharides are carbohydrates composed of two monosaccharides.
Disaccharides are acetals, compounds that contain two alkoxy groups (OR groups) bonded to the same carbon.
A disaccharide results when a hemiacetal of one monosaccharide reacts with a hydroxyl group of a second monosaccharide to form an acetal. The new C-O bond that joins the two rings together is called a glycosidic linkage.
The two monosaccharide rings may be five-membered or six-membered. All disaccharides contain at least one acetal that joins the rings together. Each ring is numbered beginning at the anomeric carbon, the carbon in each ring bonded to two oxygen atoms
An a glycoside has the glycosidic linkage oriented down, below the plane of the ring that
contains the acetal joining the monosaccharides.
A β glycoside has the glycosidic linkage oriented up, above the plane of the ring that
contains the acetal joining the monosaccharides.
(d)
Interpretation:
Whether the hemiacetal drawn as an a or β anomer should be predicted.
Concept Introduction:
Anomers are cyclic monosaccharides or glycosides that are epimers, differing from each other in the configuration of C-1 if they are aldoses or in the configuration at C-2 if they are ketoses. The epimeric carbon in anomers are known as anomeric carbon or anomeric center.
Depending on the orientation of carbon number 1 when the carbon number 5 hydroxyl bonds to it, two different forms can result.
These two forms are identical except for the configuration around C1. These two forms are called anomers.
C1 is called the anomeric carbon. If the hydroxyl group on C1 and the -CH2OH group on C5 are on opposite sides of the six-membered ring, C1 is known to be the a anomer.
If they are on the same side, C1 is known to be the β anomer.
(e)
Interpretation:
The monosaccharide formed when sophorose is hydrolyzed needs to be determined.
Concept Introduction:
Disaccharides are carbohydrates composed of two monosaccharides.
Disaccharides are acetals, compounds that contain two alkoxy groups (OR groups) bonded to the same carbon.
A disaccharide results when a hemiacetal of one monosaccharide reacts with a hydroxyl group of a second monosaccharide to form an acetal. The new C-O bond that joins the two rings together is called a glycosidic linkage.
The two monosaccharide rings may be five-membered or six-membered. All disaccharides contain at least one acetal that joins the rings together. Each ring is numbered beginning at the anomeric carbon, the carbon in each ring bonded to two oxygen atoms.
The hydrolysis of a disaccharide cleaves the C-O glycosidic linkage and forms two monosaccharides.
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Chapter 20 Solutions
General, Organic, and Biological Chemistry - 4th edition
- Q1: For each molecule, assign each stereocenter as R or S. Circle the meso compounds. Label each compound as chiral or achiral. OH HO CI Br H CI CI Br CI CI Xf x f g Br D OH Br Br H₂N R. IN Ill I -N S OMe D II H CO₂H 1/111 DuckDuckGarrow_forwardThese are synthesis questions. You need to show how the starting material can be converted into the product(s) shown. You may use any reactions we have learned. Show all the reagents you need. Show each molecule synthesized along the way and be sure to pay attention to the regiochemistry and stereochemistry preferences for each reaction. If a racemic molecule is made along the way, you need to draw both enantiomers and label the mixture as "racemic". All of the carbon atoms of the products must come from the starting material! ? H Harrow_forwardQ5: Draw every stereoisomer for 1-bromo-2-chloro-1,2-difluorocyclopentane. Clearly show stereochemistry by drawing the wedge-and-dashed bonds. Describe the relationship between each pair of the stereoisomers you have drawn.arrow_forward
- Classify each pair of molecules according to whether or not they can participate in hydrogen bonding with one another. Participate in hydrogen bonding CH3COCH3 and CH3COCH2CH3 H2O and (CH3CH2)2CO CH3COCH3 and CH₂ CHO Answer Bank Do not participate in hydrogen bonding CH3CH2OH and HCHO CH3COCH2CH3 and CH3OHarrow_forwardNonearrow_forwardQ4: Comparing (3S,4S)-3,4-dimethylhexane and (3R,4S)-3,4-dimethylhexane, which one is optically active? Briefly explain.arrow_forward
- Nonearrow_forwardNonearrow_forwardGiven the standard enthalpies of formation for the following substances, determine the reaction enthalpy for the following reaction. 4A (g) + 2B (g) → 2C (g) + 7D (g) AHrxn =?kJ Substance AH in kJ/mol A (g) - 20.42 B (g) + 32.18 C (g) - 72.51 D (g) - 17.87arrow_forward
- Determine ASran for Zn(s) + 2HCl(aq) = ZnCl2(aq) + H2(aq) given the following information: Standard Entropy Values of Various Substance Substance So (J/mol • K) 60.9 Zn(s) HCl(aq) 56.5 130.58 H2(g) Zn2+(aq) -106.5 55.10 CI (aq)arrow_forward3) Catalytic hydrogenation of the compound below produced the expected product. However, a byproduct with molecular formula C10H12O is also formed in small quantities. What is the by product?arrow_forwardWhat is the ΔHorxn of the reaction? NaOH(aq) + HCl(aq) → H2O(l) + NaCl(aq) ΔHorxn 1= ________ kJ/molarrow_forward
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