Concept explainers
Interpretation:
The reason for addition of tetraethyl lead to the gasoline in the past and the reason for this process to be phased out should be explained.
Concept Introduction:
Tetraethyl lead has been used as an antiknocking agent. Knocking is a process that occur in internal combustion engines that results in premature combustion of portions of fuel/air mixture without reaching the flame front where the fuel/air mixture should burn with the ignition that comes from spark plug. This ultimately results in an inefficient energy transfer. Gasoline (fuel) is mixed with antiknocking agents to overcome this problem. When antiknocking agents such as Tetraethyl lead are mixed with gasoline, it allows fuel/air mixture to reach higher temperature and pressure without being combusted reducing the premature combustion.
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Chapter 20 Solutions
EBK INTRO.CHEMISTRY (NASTA EDITION)
- Complete and balance the following combustion reactions. Assume that each hydrocarbon is converted completely to carbon dioxide and water. (a) Propane + O2 (b) Octane + O2 (c) Cyclohexane + O2 (d) 2-Methylpentane + O2arrow_forwardAlcohols are very useful starting materials for the production of many different compounds. The following conversions, starting with 1-butanol, can be carried out in two or more steps. Show the steps (reactants/catalysts) you would follow to carry out the conversions, drawing the formula for the organic product in each step. For each step, a major product must be produced. (See Exercise 62.) (Hint: In the presence of H+, an alcohol is converted into an alkene and water. This is the exact reverse of the reaction of adding water to an alkene to form an alcohol.) a. 1-butanol butane b. 1-butanol 2-butanonearrow_forwardWhat is the organic product? MeO₂C I MeO₂C. III CO₂Me MeO₂C II MeO₂C. IV HIIH hparrow_forward
- 85. Propane, C3H8, is a hydrocarbon that is commonly used as a fuel. (a) Write a balanced equation for the complete combustion of propane gas. (b) Calculate the volume of air at 25 °C and 1.00 atmosphere that is needed to completely combust 25.0 grams of propane. Assume that air is 21.0 percent O2 by volume. (Hint: We will see how to do this calculation in a later chapter on gases—for now use the information that 1.00 L of air at 25 °C and 1.00 atm contains 0.275 g of O2 per liter.) (c) The heat of combustion of propane is −2,219.2 kJ/mol. Calculate the heat of formation, ΔH∘fΔHf° of propane given that ΔH∘fΔHf° of H2O(l) = −285.8 kJ/mol and ΔH∘fΔHf° of CO2(g) = −393.5 kJ/mol. (d) Assuming that all of the heat released in burning 25.0 grams of propane is transferred to 4.00 kilograms of water, calculate the increase in temperature of the water.arrow_forward(a) What is the difference between chlorofluorocarbons and hydrofluorocarbons?arrow_forwardWrite a balanced equation for the combustion of liquid propanol (C3H7OH).arrow_forward
- g) H2O Hydlnde.arrow_forwardDecane has the structure: CH3(CH2)9CH3. What does the prefix "dec-" specifically indicate about the structure of this compound? Multiple Choice It contains a straight chain of carbons. It contains 10 carbons in a continuous chain. It is an alkane. It is a saturated hydrocarbon.arrow_forwarddraw three structural isomers for the alkane C5H12.arrow_forward
- Complete and balance the following combustion reaction . Assume that each hydrocarbon is converted completely to carbon dioxide and water.arrow_forwardPropane, C3H8, is a hydrocarbon that is commonly used as a fuel.(a) Write a balanced equation for the complete combustion of propane gas.(b) Calculate the volume of air at 25 °C and 1.00 atmosphere that is needed to completely combust 25.0 grams of propane. Assume that air is 21.0 percent O2 by volume. (Hint:use the information that 1.00 L of air at 25 °C and 1.00 atm contains 0.275 g of O2 per liter.)(c) The heat of combustion of propane is −2,219.2 kJ/mol. Calculate the heat of formation, ΔH°f of propane given that ΔH°f of H2O(l) = −285.8 kJ/mol and ΔH°f of CO2(g) = −393.5 kJ/mol. (d) Assuming that all of the heat released in burning 25.0 grams of propane is transferred to 4.00 kilograms of water, calculate the increase in temperature of the water.arrow_forwardEthanol, C₂H60, is most often blended with gasoline - usually as a 10 percent mix - to create a fuel called gasohol. Ethanol is a renewable resource and ethanol-blended fuels, like gasohol, appear to burn more efficiently in combustion engines. The combustion of one mole of ethanol releases 326.7 kcal of energy. The combustion of one mole of 2-methylheptane, C8H18, releases 1.306 × 10³ kcal of energy. How much energy is released during the complete combustion of 405 grams of 2- methylheptane? kcal Assuming the same efficiency, would 405 grams of ethanol provide more, less, or the same amount of energy as 405 grams of 2-methylheptane? more less the same amount Retry Entire Group 9 more group attempts remainingarrow_forward
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