Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
9th Edition
ISBN: 9781133949640
Author: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher: Cengage Learning
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Chapter 20, Problem 31PS

(a)

Interpretation Introduction

Interpretation: The balanced equation for the burning of methyl myristate has to be written.

Concept introduction:

  • Balanced chemical equation of a reaction is written according to law of conservation of mass.
  • Stoichiometry of a chemical reaction is the relation between reactants and products of the reaction and it is represented by the coefficients used for the reactants and products involved in the chemical equation.

(a)

Expert Solution
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Answer to Problem 31PS

The balanced equation for the given reaction is,

 C13H27CO2CH3(l)+432O2(g)15CO2(g)+15H2O(g)

Explanation of Solution

When methyl myristate is burned the gas CO2 and H2O are produced as the products.

The balanced equation for the combustion of methyl myristate is given as:

C13H27CO2CH3(l)+432O2(g)15CO2(g)+15H2O(g).

(b)

Interpretation Introduction

Interpretation: Enthalpy change for the oxidation of methyl myristate should be determined using the given data.

Concept introduction:

Enthalpy of combustion: At standard conditions when one mole of substance is burnt completely in presence of oxygen, the enthalpy change involved is called enthalpy of combustion.

ΔH0comb=nΔH0fproducts-nΔH0freactants

(b)

Expert Solution
Check Mark

Answer to Problem 31PS

Enthalpy change is calculated to be -8759.1kJ/mol

Explanation of Solution

Given:

ΔH0fof CO2=-393.509kJ/molΔH0fof H2O=-241.83kJ/molΔH0fofC13H27CO2CH3=-771kJ/molΔH0fofO2=0kJ/mol

Change in enthalpy can be calculated by the equation:

ΔH0comb=nΔH0fproducts-nΔH0freactants

ΔH0comb=[15×-393.509+15×-241.83]-[-771]=-8759.1kJ/mol

(c)

Interpretation Introduction

Interpretation: The fuel which provides more energy (Hexadecane or methyl myristate) should be determined.

Concept introduction:

Enthalpy of combustion: At standard conditions when one mole of substance is burnt completely in presence of oxygen, the enthalpy change involved is called enthalpy of combustion.

ΔH0comb=nΔH0fproducts-nΔH0freactants

(c)

Expert Solution
Check Mark

Answer to Problem 31PS

Hexadecane provide more energy than methyl myristate.

Explanation of Solution

For methyl myristate:

ΔH0fof CO2=-393.509kJ/molΔH0fof H2O=-241.83kJ/molΔH0fofC13H27CO2CH3=-771kJ/molΔH0fofO2=0kJ/mol

Change in enthalpy can be calculated by the equation:

ΔH0comb=nΔH0fproducts-nΔH0freactants

ΔH0comb=[15×-393.509+15×-241.83]-[-771]=-8759.1kJ/mol

For hexadecane:

ΔH0fof CO2=-393.509kJ/molΔH0fof H2O=-241.83kJ/molΔH0fofC16H34=-456.1kJ/molΔH0fofO2=0kJ/mol

2C6H34(l)+49O2(g)32CO2(g)+34H2O(g)

Change in enthalpy can be calculated by the equation:

ΔH0comb=nΔH0fproducts-nΔH0freactants

ΔH0comb=[32×-393.509+34×-241.83]-[-2×456.1]=-9951.2kJ/mol

Hexadecane provide more energy than methyl myristate.

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Chapter 20 Solutions

Chemistry & Chemical Reactivity

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