(a)
Interpretation: The
Concept introduction:
Ocean acidification: The increase in concentration of carbon-dioxide in the atmosphere leads to ocean acidification. The amount is increasing day by day and this increase will lead to higher concentrations of dissolved
The concentration of hydronium ion is a key factor for many biochemical reactions. So variation may affect the organisms in the oceans.
The relationship between ocean
(a)
Answer to Problem 40GQ
The
Explanation of Solution
If the concentration of dissolved
The graph showing the fraction of species in the solution as a function of
From the graph we can identify the
The fraction of dissociation will be 0.50 when the concentration of both the species will be equal.
The
(b)
Interpretation: The
Concept introduction:
Ocean acidification: The increase in concentration of carbon-dioxide in the atmosphere leads to ocean acidification. The amount is increasing day by day and this increase will lead to higher concentrations of dissolved
The concentration of hydronium ion is a key factor for many biochemical reactions. So variation may affect the organisms in the oceans.
The relationship between ocean
(b)
Answer to Problem 40GQ
The
Explanation of Solution
If the concentration of dissolved
The graph showing the fraction of species in the solution as a function of
From the graph we can identify the
The fraction of dissociation will be 0.50 when the concentration of both the species will be equal.
The
(c)
Interpretation: The predominant species in the solution when the
Concept introduction:
Ocean acidification: The increase in concentration of carbon-dioxide in the atmosphere leads to ocean acidification. The amount is increasing day by day and this increase will lead to higher concentrations of dissolved
The concentration of hydronium ion is a key factor for many biochemical reactions. So variation may affect the organisms in the oceans.
The relationship between ocean
(c)
Answer to Problem 40GQ
The predominant species in the solution when the
Explanation of Solution
If the concentration of dissolved
The graph showing the fraction of species in the solution as a function of
When the
From the graph it is clear that, the predominant species when the
(d)
Interpretation: The predominant species in the solution when the
Concept introduction:
Ocean acidification: The increase in concentration of carbon-dioxide in the atmosphere leads to ocean acidification. The amount is increasing day by day and this increase will lead to higher concentrations of dissolved
The concentration of hydronium ion is a key factor for many biochemical reactions. So variation may affect the organisms in the oceans.
The relationship between ocean
(d)
Answer to Problem 40GQ
The predominant species in the solution when the
Explanation of Solution
If the concentration of dissolved
The graph showing the fraction of species in the solution as a function of
When the
From the graph it is clear that, the predominant species when the
Want to see more full solutions like this?
Chapter 20 Solutions
Chemistry & Chemical Reactivity
- Write the equilibrium constant expression of the reaction.arrow_forwardBecause of the toxicity of mercury compounds, mercury(I)chloride is used in antibacterial salves. The mercury(I) ion(Hg₂²⁺) consists of two bound Hg⁺ ions.(a) What is the empirical formula of mercury(I) chloride?(b) Calculate [Hg₂²⁺] in a saturated solution of mercury(I) chlo-ride (Ksp=1.5X10⁻¹⁸).(c) A seawater sample contains 0.20 lb of NaCl per gallon. Find[Hg₂²⁺] if the seawater is saturated with mercury(I) chloride.(d) How many grams of mercury(I) chloride are needed to satu-rate 4900 km³ of pure water (the volume of Lake Michigan)?(e) How many grams of mercury(I) chloride are needed to satu-rate 4900 km³ of seawater?arrow_forwardCalculate the ratio of dihydrogen phosphate to hydrogen phosphate in blood at pH 7.4. The Ka is 6.3 × 10−8.arrow_forward
- There are many organic acids and bases in our cells, and their presence modifies the pH of the fluids inside them. It is useful to be able to assess the pH of solutions of acids and bases and to make inferences from measured values of the pH. A solution of equal concentrations of lactic acid and sodium lactate was found to have pH= 3.08. (a) What are the values of pKa and Ka of lactic acid? (b) What would the pH be if the acid had twice the concentration of the salt?arrow_forwardIn the following reaction, identify the role of each species: NO3-(aq) + 4H+(aq) + Cr(s) → Cr3+(aq) + NO(g) + 2H2O(l) Oxidized: Reduced: Oxidizing Agent/Oxidant: Reducing Agent/Reductanarrow_forwardChemistry Like aqueous solutions of Fe3+, bismuth ions (Bi3+) form acidic solutions with a pKa = 1.5. (a) Write a balanced net ionic equation for the reaction of Bi3+ with water to form a dication, [Bi(H2O)5OH]2+. (b) What is the pH of a 0.00364 M solution of Bi3+? (c) How is the acidity of this solution (0.00364 M Bi3+ ions) related to the acidity of a 0.00364 M acetic acid aqueous solution? A. Bi3+ is less acidic than acetic acid. B. Bi3+ is more acidic than acetic acid. C. There is not enough information to tell which is more acidic. D. Bi3+ and acetic acid have the same acidity.arrow_forward
- 3. Is the reaction Co(H2O)6²+(aq) + 4 Cl'(aq) → CoCl,²- (aq) + 6 H2O (I) endo or exothermic? Explain.arrow_forwardWhat is the equilibrium constantarrow_forward(a) Given the Ksp of calcium phosphate, Ca3(PO4)2 is 1.3 × 1032. Calculate concentrations of Ca2+ and PO43− respectively. (b) If a hard water contains 75 mg/L of Ca2+, at what concentration of PO43- would a precipitate of Ca3(PO4)2 begin to appear?arrow_forward
- Consider the photochemical isomerization A B. At 650. nm, the quantum yields for the forward and reverse reactions are 0.83 and 0.52, respectively. If the molar absorptivities at 650. nm of A and B are 1.2×103 L·mol-1.cm-1 and 4.5×102 L·mol-1.cm-1, respectively, what is the ratio [B]/[A] in the photostationary state? [B] [A] = 4.0arrow_forwardA solution of tyrosine is made by dissolving 0.005 mole of tyrosine in 1.0 L of 0.1 M NaOH solution. Draw the structure of the principal chemical form of tyrosine found in this solution at equilibrium given the data below. NH2 pKa (CO2H) = 2.41 pKa (NH2) = 8.67 pka (OH) = 11.01 CHCH2 OH CO2Harrow_forward25b. At a particular temperature, the solubility of In₂(SO₄)₃ in water is 0.0068 M. You have found Ksp to be 1.6 × 10⁻⁹. If solid In₂(SO₄)₃ is added to a solution that already contains 0.200 M Na₂SO₄, what will the new solubility of the solid be?arrow_forward
- General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning