A proposed mechanism for the gas-phase chlorination of methane is Cl 2 + CH 4 → CH 4 Cl + Cl ⋅ CH 4 Cl → CH 3 ⋅ + HCl CH 3 ⋅ + Cl 2 → CH 3 Cl + Cl ⋅ Cl ⋅ + CH 4 → CH 3 ⋅ + HCl Suppose the first step is the RDS. What is the expected rate law in terms of the original reactants, Cl 2 and CH 4 ? How would you determine if this mechanism might be a potentially correct (or, for that matter, a potentially incorrect) one?
A proposed mechanism for the gas-phase chlorination of methane is Cl 2 + CH 4 → CH 4 Cl + Cl ⋅ CH 4 Cl → CH 3 ⋅ + HCl CH 3 ⋅ + Cl 2 → CH 3 Cl + Cl ⋅ Cl ⋅ + CH 4 → CH 3 ⋅ + HCl Suppose the first step is the RDS. What is the expected rate law in terms of the original reactants, Cl 2 and CH 4 ? How would you determine if this mechanism might be a potentially correct (or, for that matter, a potentially incorrect) one?
Solution Summary: The author explains that the expected rate law for the chlorination of methane is to be determined. The rate of reaction depends on several factors such as the concentration of reactant and temperature.
Suppose the first step is the RDS. What is the expected rate law in terms of the original reactants,
Cl
2
and
CH
4
? How would you determine if this mechanism might be a potentially correct (or, for that matter, a potentially incorrect) one?
Draw the curved-arrow mechanism with the drawings of the molecules, not
just abbreviations.
-NO₂
Sn, HCl (aq)
E
D
H
(CH3CO)₂O
-NH2
CH3
What is/are the product(s) of the following reaction? Select all that apply.
* HI
A
B
C
OD
OH
A
B
OH
D
C
In the image, the light blue sphere represents a mole of hydrogen atoms, the purple or teal spheres represent a mole of a conjugate base. A light blue sphere by itself is H+.
Assuming there is 2.00 L of solution, answer the following:
The Ka of the left & right solution is?
The pH of the left & right solution is?
The acid on the left & right is what kind of acid?
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.