At room temperature ( 22 ° C ) , the rate constant for proton transfer between water molecules in solution is about 1 × 10 11 s − 1 , which is one of the fastest known reactions in a condensed phase. If the activation energy for this process equals one-half of the O − H bond strength of 498 kJ / mol , what is the pre-exponential factor A for this reaction?
At room temperature ( 22 ° C ) , the rate constant for proton transfer between water molecules in solution is about 1 × 10 11 s − 1 , which is one of the fastest known reactions in a condensed phase. If the activation energy for this process equals one-half of the O − H bond strength of 498 kJ / mol , what is the pre-exponential factor A for this reaction?
Solution Summary: The author explains that the value of pre-exponential factor A for the proton transfer reaction between water molecules is to be calculated.
At room temperature
(
22
°
C
)
, the rate constant for proton transfer between water molecules in solution is about
1
×
10
11
s
−
1
, which is one of the fastest known reactions in a condensed phase. If the activation energy for this process equals one-half of the
O
−
H
bond strength of
498
kJ
/
mol
, what is the pre-exponential factor
A
for this reaction?
Relative Intensity
Part VI. consider the multi-step reaction below for compounds
A, B, and C.
These compounds were subjected to mass spectrometric analysis and
the following spectra for A, B, and C was obtained.
Draw the structure of B and C and match all three compounds
to the correct spectra.
Relative Intensity
Relative Intensity
100
HS-NJ-0547
80
60
31
20
S1
84
M+
absent
10
30
40
50
60
70
80
90
100
100-
MS2016-05353CM
80-
60
40
20
135 137
S2
164 166
0-m
25
50
75
100
125
150
m/z
60
100
MS-NJ-09-43
40
20
20
80
45
S3
25
50
75
100
125
150
175
m/z
Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following:
(a) match structures of isomers given their mass spectra below (spectra A and spectra B)
(b) Draw the fragments given the following prominent peaks from
each spectrum:
Spectra A m/2 =43 and 1/2-57
spectra B m/2 = 43
(c) why is 1/2=57 peak in spectrum A more intense compared
to the same peak in spectrum B.
Relative abundance
Relative abundance
100
A
50
29
29
0
10
-0
-0
100
B
50
720
30
41
43
57
71
4-0
40
50
60 70
m/z
43
57
8-0
m/z = 86
M
90 100
71
m/z = 86
M
-O
0
10 20 30
40 50
60
70
80
-88
m/z
90
100
Part IV. C6H5 CH2CH2OH is an aromatic compound which was subjected to Electron Ionization - mass
spectrometry (El-MS) analysis. Prominent m/2 values: m/2 = 104 and m/2 = 9) was obtained.
Draw the structures of these fragments.
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